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Class 10 > If sin A=1/2, then find the value of cos A.
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If sin A=1/2, then find the value of cos A.

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CSAT Tutor, BPSC DI Tutor (Ex. Drishti IAS Senior Content Writer)

sin (A/2)= 1/2 =sin (A/2)=sin (30°)=sin(180-30) A/2= 30° or 150° A= 60° or 300° sin(A)=sin (60°)=√3/2 sin(A)=sin (300°)=sin(360°+ -60°)=sin(-60°)=-sin (60°)=(-√3)/2 sin A= ±(√3/2) formula used: sin x= sin(180°-x) sin (360°...
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sin (A/2)= 1/2 =sin (A/2)=sin (30°)=sin(180-30) A/2= 30° or 150° A= 60° or 300° sin(A)=sin (60°)=√3/2 sin(A)=sin (300°)=sin(360°+ -60°)=sin(-60°)=-sin (60°)=(-√3)/2 sin A=±(√3/2) formula used: sin x= sin(180°-x) sin (360° +x)=sin(x) sin(-x)=-sin(x) read less
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?3/2
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IT Professional with 8 years of Experience taking Tuitions.

SinA = Opp/hyptoneuse CosA = Base/Hyp so Cos A = sqrt3/2 SinA = 1/2 Opposite side = 1 Hyp side =1 2 By pythogeras theorem, Base=sqrt(Hyp^2 - Opp^2) Base = sqrt(4 - 1) Base = sqrt3
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sinA=1\2;sinA=op\h;applybypt;cosA=sqrot3\2
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Tutor

√3/2
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Chemistry Teacher

Sin^2 A + Cos^2 A =1 (1/2)^2 + cos^2 A =1 Cos A = √ CosA =√(3/4) CosA =√(3) /2
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Trainer

sin A = 1/2 sin A= sin 30 (degree) so, A = 30degree. Therefore Cos A= Cos 30degree =root3/2 = 0.8660 that is the Answer. Thank you.
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Tutor

Sin^A + Cos^A=1...so if SinA= 1/2..then Sin^A= 1/4..so Cos^A= 3/4...Hence Cos A=sqrt3/2
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Mathematics Professor

SinA=1/2 but Sin30°=1/2 hence A=30° CosA=cos30°=√3/2
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atics pecialise in mba / economics students of all levels

by Trignometry formula Sin A+ Cos A = 1, then Cos A = 1- sin A or 1-1/2 = 1/2 . 1/2 is the value of Cos A.. is the answer..K S Velmurugan
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