Chikkabellandur, Bangalore Details verified of Shubham Agrawal✕
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NIT Durgapur 2019
Bachelor of Technology (B.Tech.)
Chikkabellandur, Bangalore, India - 560035
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Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
1
Board
CBSE
Subjects taught
Mathematics, Science
Taught in School or College
Yes
Answered on 20/04/2022 Learn CBSE - Class 2/Maths/Mental Arithmetic
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Post a Lesson
Let the Present age of P be 5x and Q be 7x.
Note: The present age should be taken such that the ratio is 5:7
Present age of P and Q after 6 years: (5x+6) and (7x+6) respect belt.
Given that the difference of Q's age and P's age after 6 years in 2,
(7x+6)-(5x+6) = 2 => 2x=2 => x=1
Hence,
P's present age: 5
Q's present age : 7
Total age of P's and Q's present age = 5 + 7 = 12
Note: Take cues from the statements in the questions and try to represent the statements in the form of mathematics equations.
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Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
1
Board
CBSE
Subjects taught
Mathematics, Science
Taught in School or College
Yes
Answered on 20/04/2022 Learn CBSE - Class 2/Maths/Mental Arithmetic
Ask a Question
Post a Lesson
Let the Present age of P be 5x and Q be 7x.
Note: The present age should be taken such that the ratio is 5:7
Present age of P and Q after 6 years: (5x+6) and (7x+6) respect belt.
Given that the difference of Q's age and P's age after 6 years in 2,
(7x+6)-(5x+6) = 2 => 2x=2 => x=1
Hence,
P's present age: 5
Q's present age : 7
Total age of P's and Q's present age = 5 + 7 = 12
Note: Take cues from the statements in the questions and try to represent the statements in the form of mathematics equations.
Like 0 Answers 353 Comments Ask a Question
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Bangalore
