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Deepak Mishra Class 10 trainer in Varanasi/>

Deepak Mishra

Kandawa, Varanasi, India - 221106.

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Overview

I'm a teacher having teaching experience of more than 7 years , i teach english, hindi, social science. I'm giving online tuitions to students from different mediums since COVID has been started, My key skills are that i made my students to build a different perspective to understand the subject better. I love teaching children because there i can provide them with the knowledge I have which will help them to build a great life for themselves.

Languages Spoken

Hindi Mother Tongue (Native)

English Proficient

Telugu Basic

Education

Jntuk University 2013

Bachelor of Technology (B.Tech.)

Address

Kandawa, Varanasi, India - 221106

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Teaches

Class 10 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

7

Board

CBSE, State, NIOS

Preferred class strength

Group Classes, One on one/ Private Tutions

Subjects taught

Hindi, Social Science, English

Taught in School or College

Yes

Reviews

No Reviews yet!

FAQs

1. Which school boards of Class 10 do you teach for?

CBSE, State and NIOS

2. Do you have any prior teaching experience?

Yes

3. Which classes do you teach?

I teach Class 10 Tuition Class.

4. Do you provide a demo class?

Yes, I provide a free demo class.

5. How many years of experience do you have?

I have been teaching for 7 years.

Answers by Deepak Mishra (1)

Answered on 11/10/2023 Learn CBSE - Class 10

The law followed when balancing a chemical equation is the law of conservation of mass, which states that matter cannot be created or destroyed, only rearranged.To balance the given equation: Na + H3O → NaOH + H2Start by counting the atoms of each element on both sides of the equation:Sodium (Na):... ...more

The law followed when balancing a chemical equation is the law of conservation of mass, which states that matter cannot be created or destroyed, only rearranged.To balance the given equation: Na + H3O → NaOH + H2Start by counting the atoms of each element on both sides of the equation:Sodium (Na): 1 on the left, 1 on the rightHydrogen (H): 3 on the left (from H3O), 2 on the right (from NaOH and H2)Oxygen (O): 1 on the left (from H3O), 1 on the right (from NaOH)To balance it, you can add a coefficient in front of NaOH to make the number of hydrogen atoms equal on both sides. This equation is now balanced:2Na + 2H3O → 2NaOH + H2

Answers 60 Comments
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Teaches

Class 10 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Years of Experience in Class 10 Tuition

7

Board

CBSE, State, NIOS

Preferred class strength

Group Classes, One on one/ Private Tutions

Subjects taught

Hindi, Social Science, English

Taught in School or College

Yes

No Reviews yet!

Answers by Deepak Mishra (1)

Answered on 11/10/2023 Learn CBSE - Class 10

The law followed when balancing a chemical equation is the law of conservation of mass, which states that matter cannot be created or destroyed, only rearranged.To balance the given equation: Na + H3O → NaOH + H2Start by counting the atoms of each element on both sides of the equation:Sodium (Na):... ...more

The law followed when balancing a chemical equation is the law of conservation of mass, which states that matter cannot be created or destroyed, only rearranged.To balance the given equation: Na + H3O → NaOH + H2Start by counting the atoms of each element on both sides of the equation:Sodium (Na): 1 on the left, 1 on the rightHydrogen (H): 3 on the left (from H3O), 2 on the right (from NaOH and H2)Oxygen (O): 1 on the left (from H3O), 1 on the right (from NaOH)To balance it, you can add a coefficient in front of NaOH to make the number of hydrogen atoms equal on both sides. This equation is now balanced:2Na + 2H3O → 2NaOH + H2

Answers 60 Comments
Dislike Bookmark

Deepak Mishra conducts classes in Class 10 Tuition. Deepak is located in Kandawa, Varanasi. Deepak takes Online Classes- via online medium. He has 7 years of teaching experience . Deepak has completed Bachelor of Technology (B.Tech.) from Jntuk University in 2013. HeĀ is well versed in Telugu, Hindi and English.

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