Nadesar, Varanasi, India - 221002.
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Hindi Mother Tongue (Native)
English Proficient
Sri Baldev P.G.College 1985
Bachelor of Science (B.Sc.)
Nadesar, Varanasi, India - 221002
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Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
15
Board
State, CBSE, ISC/ICSE
ISC/ICSE Subjects taught
Chemistry, Mathematics, Physics
CBSE Subjects taught
Mathematics, Physics, Chemistry
Taught in School or College
No
State Syllabus Subjects taught
Chemistry, Mathematics, Physics
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Engineering Entrance Coaching classes
20
Engineering Entrance Exams
IIT JEE Coaching Classes, BITSAT Coaching Classes
IITJEE Coaching
IIT JEE Foundation Course, IIT JEE Crash Course, IIT JEE Advanced Coaching, IIT JEE Mains Coaching
Type of class
Regular Classes, Crash Course
IIT-JEE Subjects
Physics
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Medical Entrance Coaching classes
15
Teaches for following exams
PMT Coaching, AIPMT Coaching
Type of class
Regular Classes, Crash Course
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 11 Tuition
20
Board
CBSE, ISC/ICSE
CBSE Subjects taught
Physics
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
20
Board
ICSE, CBSE
CBSE Subjects taught
Mathematics, Science
ICSE Subjects taught
Physics, Mathematics
Taught in School or College
No
1. Which school boards of Class 12 do you teach for?
State, CBSE and ISC/ICSE
2. Have you ever taught in any School or College?
No
3. Which classes do you teach?
I teach Class 10 Tuition, Class 11 Tuition, Class 12 Tuition, Engineering Entrance Coaching and Medical Entrance Coaching Classes.
4. Do you provide a demo class?
Yes, I provide a free demo class.
5. How many years of experience do you have?
I have been teaching for 15 years.
Answered on 24/06/2019 Learn Tuition
According to polynomial formula below is the equation.
x3 +y3 +z3 –3xyz=(x+y+z)(x2 +y2 +z2 –xy–yz–zx)
But in the question it is given that
Use this value in polynomial equetion.
x3 +y3 +z3 –3xyz=(x+y+z)(0)
x3 +y3 +z3 –3xyz=0
x3 +y3 +z3 =3xyz
So, 3xyz is your solution.
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
15
Board
State, CBSE, ISC/ICSE
ISC/ICSE Subjects taught
Chemistry, Mathematics, Physics
CBSE Subjects taught
Mathematics, Physics, Chemistry
Taught in School or College
No
State Syllabus Subjects taught
Chemistry, Mathematics, Physics
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Engineering Entrance Coaching classes
20
Engineering Entrance Exams
IIT JEE Coaching Classes, BITSAT Coaching Classes
IITJEE Coaching
IIT JEE Foundation Course, IIT JEE Crash Course, IIT JEE Advanced Coaching, IIT JEE Mains Coaching
Type of class
Regular Classes, Crash Course
IIT-JEE Subjects
Physics
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Medical Entrance Coaching classes
15
Teaches for following exams
PMT Coaching, AIPMT Coaching
Type of class
Regular Classes, Crash Course
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 11 Tuition
20
Board
CBSE, ISC/ICSE
CBSE Subjects taught
Physics
Taught in School or College
No
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
20
Board
ICSE, CBSE
CBSE Subjects taught
Mathematics, Science
ICSE Subjects taught
Physics, Mathematics
Taught in School or College
No
Answered on 24/06/2019 Learn Tuition
According to polynomial formula below is the equation.
x3 +y3 +z3 –3xyz=(x+y+z)(x2 +y2 +z2 –xy–yz–zx)
But in the question it is given that
Use this value in polynomial equetion.
x3 +y3 +z3 –3xyz=(x+y+z)(0)
x3 +y3 +z3 –3xyz=0
x3 +y3 +z3 =3xyz
So, 3xyz is your solution.
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