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If cos theta =1/root2 then find the value of 4+cot theta

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Cos theta = 1/root 2 Cos theta = cos 45 Theta = 45 Now cot 45 = 1 4+cot 45 = 4+1=5
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If cos theta is 1/root 2... then you see in t-ratio table.. cos attains value 1/root 2 at 45° which means value of theta is 45° .. then find the value of cot 45° .. which is 1.. then 4+1 =5
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Cos theta = 1/root 2 Cos the theta = cos 45 Theta = 45 Now cot 45 = 1 So 4 + cot 45 = 4+1=5
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From the given condition, CosΘ = 1/√2 CosΘ = Cos45º ∴ Θ = 45º Now, 4 + CotΘ = 4 + Cot45º = 4 + 1 = 5
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From the given condition, CosΘ = 1/√2 CosΘ = Cos45º ∴ Θ = 45º Now, 4 + CotΘ = 4 + Cot45º = 4 + 1 = 5 read less
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Given, Therefore, . Therefore, . 4+
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Given, Therefore,. Therefore,. 4+ read less
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cos=1/, = , 4+cot = 4+1 =5
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cos=1/,= , 4+cot = 4+1 =5 read less
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1. Cos Θ= 1\√2 2. Θ= 45° 3. Cot 45°= 1 4. 4+ cot45°= 5
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Cos theta = 1/√2 Hence theta is 45° Now, 4+ Cot theta= 4+ Cot 45°=4+1=5
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