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# If cos theta =1/root2 then find the value of 4+cot theta

Teacher , Friend , Motivator & Philospher

Cos theta = 1/root 2 Cos theta = cos 45 Theta = 45 Now cot 45 = 1 4+cot 45 = 4+1=5

Specialist of maths and science for class 9th and 10th

Teacher , Friend , Motivator & Philospher

Cos theta = 1/root 2 Cos the theta = cos 45 Theta = 45 Now cot 45 = 1 So 4 + cot 45 = 4+1=5

Teaching is not a profession, it's a responsibility.

If cos theta is 1/root 2... then you see in t-ratio table.. cos attains value 1/root 2 at 45° which means value of theta is 45° .. then find the value of cot 45° .. which is 1.. then 4+1 =5

From the given condition, CosΘ = 1/√2 CosΘ = Cos45º ∴ Θ = 45º Now, 4 + CotΘ = 4 + Cot45º = 4 + 1 = 5

From the given condition,

CosΘ = 1/√2

CosΘ = Cos45º

∴ Θ = 45º

Now,

4 + CotΘ = 4 + Cot45º

= 4 + 1

= 5

Tutor for Mechanical Engg Subjects And Mathe Matics & Physics

cos=1/, = , 4+cot = 4+1 =5

cos$\Theta$=1/$\sqrt{2}$$\Theta$=$45^{\circ}$ ,

4+cot$45^{\circ}$ = 4+1 =5

Classes for Mathematics and Physics

1. Cos Θ= 1\√2 2. Θ= 45° 3. Cot 45°= 1 4. 4+ cot45°= 5

9 years teaching experience in educational industry

Given, Therefore, . Therefore, . 4+

Given,

$cos\Theta&space;=&space;\frac{1}{\sqrt{2}}$

Therefore, $cos\Theta&space;=cos\Pi&space;/4$.

Therefore, $\Theta&space;=\Pi&space;/4$.

4+$cot\Theta&space;=&space;4+cot\Pi&space;/4=4+1=5.$

5

Getting better is a process that should never stop.

Cos theta = 1/√2 Hence theta is 45° Now, 4+ Cot theta= 4+ Cot 45°=4+1=5

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