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Answered on 23 Mar CBSE/Class 11/Science/Physics Tuition/Class IX-X Tuition

Sonu Kumar Meena

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Answers 19 Comments Answered on 29 Sep CBSE/Class 10/Social Studies Tuition/Class IX-X Tuition

Velmurugan K S

Associate Professor

It appears that agriculture ..lot of people 80 to 90 was in it in 190..by now in2018..dependant ratio is 50%..Are engaged but productivity is low .because of poor monsoons..& no govt support..it is Tertial sector comprising of banks, Telecom., services of all kinds from productive like electric,... read more

It appears that agriculture ..lot of people 80 to 90 was in it in 190..by now in2018..dependant ratio is 50%..Are engaged but productivity is low .because of poor monsoons..& no govt support..it is Tertial sector comprising of banks, Telecom., services of all kinds from productive like electric, hydro power .coal and oil & infrastructure like road, railways, air & sea transport. Trade , commerce , shipping , P& T service .telephone services , education , legal ,contribute more than 40 % of our GDP..there fore future depend on that sector in india..as in majority of countries of modern world..Dr K S Velmurugan , KMCPGS Pondicherry

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Answers 8 Comments Answered on 23 Feb CBSE/Class 9/Mathematics Tuition/Class IX-X Tuition

Salman Ahmad Siddiqui

Expert Tutor

2x + 3y=7 Put 2 in place of x and 1 in place of y. 2*2+ 3*1=4+3=7

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Answers 27 Comments Looking for Class 10 Tuition

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Lesson Posted on 18/06/2017 CBSE/Class 10/Science Tuition/Class VI-VIII Tuition Tuition/Class IX-X Tuition

Numerical problems on force and pressure

Soumi Roy

I am an experienced, qualified tutor with over 5 years of experience in teaching maths and physics across...

Example 1: A force of 1200 N acts on the surface of area 10 cm2 normally. What would be the thrust and pressure on the surface?Given: Force F = 1200 N, Area A = 10 cm2 = 10 ×10-4 m2 = 10-3 m2Thrust = Normal pressure = F = 1200 NPressure P = F/A 1200N10−3m21200N10−3m2 ... read more

**Example 1:**

A force of 1200 N acts on the surface of area 10 cm^{2} normally. What would be the thrust and pressure on the surface?

Given:

Force F = 1200 N, Area A = 10 cm^{2} = 10 ×10^{-4} m^{2} = 10^{-3} m^{2}

Thrust = Normal pressure = F = 1200 N

Pressure P = F/A 1200N10−3m21200N10−3m2

= 1.2 ×× 10^{6} N/m^{2}

**Example 2****:**

The elephant weighs 20,000 N stands on one foot of area 1000 cm^{2}. How much pressure would it exert on the ground?

Given:

Force applied by elephant F = 20,000 N, area A = 1000 cm^{2} = 1000/100×100m^{2 }= 0.1 m^{2}

The pressure is given by

Pressure P = F/A

= 20,000N/0.1m2

= 2,00,000 N/m^{2}.

**Example 3:**

Calculate the pressure produced by a force of 800 N acting on an area of 2.0 m^{2}.

**Solution:**

Pressure is defined as force per unit area or P = F / A

P = (800 N) / (2.0 m2

)

P = 400 N / m2

= 400 Pa

**Example 4:**

The pressure of a gas contained in a cylinder with a movable piston is 300 Pa. The area of the piston is 0.5 m^{2}. Calculate the force that is exerted on the piston.

**Solution**

Pressure is defined as force per unit area or P = F / A

We multiply both sides of the equation by the area to solve for the force as

F = P A

F = (300 Pa) (0.5 m2

)

F = 150 (Pa) m2

= 150 (N / m2

) m2

F = 150 N

**Example 5:**

A swimming pool of width 9.0 m and length 24.0 m is filled with water to a depth of 3.0 m. Calculate pressure on the bottom of the pool due to the water.

**Solution:**

The pressure due to a column of fluid is calculated as the product of the height of the fluid times

the density of the fluid times the acceleration due to gravity. For water the density is d = 1000 kg /

m3

.

? P = d h g

? P = (1000 kg / m3

) (3.0 m) (9.8 m / s2

)

? P = 29400 kg m2 / m3

s2

To simplify the units we cancel one m term in the m2

term in the numerator and one m term in

the m3

term in the denominator to get

? P = 29400 kg m / s2

m2

We know that 1N = 1 kg m / s2

so we can write

? P = 29400 N / m2

= 29400 Pa

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Comments 15 Answered on 06/06/2017 Tuition/Class IX-X Tuition

Winning Edge Academy.

Cos360= Cos(360+0)=Cos0=1

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Answers 192 Comments Answered on 01/05/2017 CBSE/Class 10/Mathematics Tuition/Class IX-X Tuition

Ishaan Srivastava

Tutor

Every Prime number has exactly two factors, 1 and itself, and not divisible by any other number, Using the same logic, 0 is divisible 3 , 4 , 5 , 6 and so on, Such as ( 0 x 3 = 0 , 0 x 4 = 0 .......). Hence it has more than 2 factor and is not a Prime Number.

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Answers 425 Comments 2 Looking for Class 10 Tuition

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Answered on 01/10/2016 Tuition/Class IX-X Tuition Tuition/Class IX-X Tuition/Social science

Anurag Sharma

Enjoy teaching

Seasonal unemployment occurs when people are unable to find jobs during some months of the year. This kind of unemployment is generally found in agricultural sector.

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Answers 11 Comments 2 Answered on 08/12/2015 Tuition/Class IX-X Tuition

Shilpa D.

Santushti apartment D6 vasant kunj Group classes maths and science

That depend on subject to subject because more tough the subject more it will be charged. But there are few tutors who are taking small amount for the classes. So most of students went there.

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Answers 80 Comments Answered on 17/03/2015 Tuition/Class IX-X Tuition

Uma Swapna C.

I am Pharmaceutical Biotechnologist (MPHARM) passionate about teaching. Conscientious in nature that...

sulphuric acid

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Answered on 31/01/2015 Tuition/Class IX-X Tuition

Rashmi K.

Science and Maths teacher till class 10

The minimum distance required for an echo to be produced is 16.6 m. Consider an observer producing a sound at a distance x from a rigid surface. The person hears the first sound as soon as it is produced and next when it travels through a total distance of 2x i.e. (x+x) for approaching the surface and... read more

The minimum distance required for an echo to be produced is 16.6 m. Consider an observer producing a sound at a distance x from a rigid surface. The person hears the first sound as soon as it is produced and next when it travels through a total distance of 2x i.e. (x+x) for approaching the surface and and for returning to the observer.Since the standard speed of sound internationally accepted is 332 m/s and to hear the 2 sounds distinctly i.e., for formation of echo, the minimum speed required is 0.1 second. Accordingly, Speed(S)=Distance(d)/Time(t) or, distance = speed*time or, 2x = 332 m/s * 0.1 s s and s gets cancelled.. or, x = 332 *0.1 m /2 or, x = 33.2 m /2 or, x = 16.6 m (Answer) read less

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