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Lesson Posted on 29 Jul IT Courses/Datastage Exam Coaching/Engineering Entrance Coaching

To become a software engineer.

Venkata Ramana

Having total experience is 10.3 years on ETL Tool "Datastage" in Data Warehousing Technologies in MNCs....

It requires a burning desire to become a software engineer by choosing a platform ( Eg: Data Warehousing, DBA,.Net, Java, etc.). Attend the primary skillset and secondary skillset courses without fail. Should concentrate more on primary skillset along with Secondary skill set. Attend the no. of interviews... read more

It requires a burning desire to become a software engineer by choosing a platform ( Eg: Data Warehousing, DBA,.Net, Java, etc.).

Attend the primary skillset and secondary skillset courses without fail.

Should concentrate more on primary skillset along with Secondary skill set.

Attend the no. of interviews and gather the information by communicating with Trainer and Working employees.

Note: Interview failure is an indication of success.
Don't go to lean other platform technologies until and unless dependency because of time waste, money waste, energy waste, etc.

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Answered on 23 Jul Exam Coaching/Engineering Entrance Coaching/GATE Coaching/Architecture and Planning

Paramita

Maths and Science Female Tutor

You have to appear for AIEEE.
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Answered on 30 Jul Exam Coaching/Engineering Entrance Coaching/GATE Coaching/Architecture and Planning

Mayank Maheshwari

Mathematician and It Person Having More Than 15 Years Experience

You have various institutions for this course but for best institutions, you have to prepare for JEE and AIEEE exam.
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Lesson Posted on 13 Jul CBSE/Class 12/Science/Physics/Unit 3-Magnetic Effect of Current & Magnetism Exam Coaching/NEET-UG Coaching Exam Coaching/Engineering Entrance Coaching/IIT JEE Coaching/IIT JEE Foundation Course +1 Exam Coaching/Engineering Entrance Coaching/IIT JEE Coaching/IIT JEE Mains Coaching less

Cyclotron Working

Institute of Conceptual Physics

Finding Physics Too Tough ? We can make it simple for you. Majority of Science Students suffer because...

Brief Intro to Cyclotron: The cyclotron is very important for Class XII Students. Its asked as a Long Answer Question in Class XII Examination. Linear Accelerators versus Cyclotron There are Linear Accelerators available, but Cyclotrons are Better for accelerating the charged particle because they... read more

Brief Intro to Cyclotron:

The cyclotron is very important for Class XII Students. Its asked as a Long Answer Question in Class XII Examination.

Linear Accelerators versus Cyclotron

There are Linear Accelerators available, but Cyclotrons are Better for accelerating the charged particle because they make the charged particle move in a Spiral and Hence the size of Cyclotron is manageable when compared to a Linear Accelerator. So a Cyclotron is Compact!

Best way to learn Cyclotron

1. One should study Each Part of Cyclotron ( Construction) and Understand its usage. Each Part of Cyclotron plays an Important part in working of Cyclotron.  The Main components of Cyclotron are:-

a) Dees -These are the Hollow Containers. The 2 Dees has a Small Gap between them.

b) Dees are connected to an Alternating Voltage Source (Not Direct Voltage)

c) Both the Dees are inside a magnetic field B.

d) There is a charged particle (using an Ion Source) which is sent at the centre of the Cyclotron into a Dee ( any of the two).

e) The Magnetic Field makes the Charge Particle move into a Circle.

f)  When the charged particle completes the semi-circle in a Dee the alternating voltage comes into play, i.e. the polarity is changed, and the charged particle is accelerated towards the other D using Alternating Voltage through the Gap between the 2 Dees.

g) The Charged particle again moves in a circle under the influence of the Magnetic Field but this time with larger radius because it went in with higher speed provided by the Alternating Voltage.

h) The process explained from e) to g) is repeated many times. The charged particle keeps on gaining velocity and moves spirally. ( Spiral means the Radius of the circle increases when it enters the other Dee, so the shape of motion is Spiral).

i) The charged particle is thus made to pass across the same electric field ( produced by Alternating Voltage) and Magnetic field.

2. The most crucial concept in Cyclotron is understanding the frequency of revolution as the Radius increases. Read that carefully as this point gets missed. The Period of the cyclotron is the time for which it stays inside the Dee.

3. The Best way to study Cyclotron is to first under the Physics Laws that Governs the working of Cyclotron. The Magnetic Field provides the required Centripetal Force to the Cyclotron for circular motion, and Electric field provides it with the Required Linear acceleration, i.e. increase in velocity.

4. A Cyclotron keeps on increase the Velocity and hence Kinetic Energy of the Charged Particle.

In medical science, Cyclotrons are used to Treat Cancer by providing Proton Therapy. The accelerated Protons penetrate the body to destroy the Tumour.

Electrons are generally not accelerated using a cyclotron because they have very light mass. If they are accelerated the speed becomes very very high. The speed change should be in synch with the frequency of the electric field.

Challenge Question What is the use of Oscillator (source of the electric field) connected to Cyclotron? How does the Frequency of Cyclotron impact the working of Cyclotron?

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Lesson Posted on 15 Jun CBSE/Class 10/Science/Unit IV: Effects of Current/Magnetic Effects of Electric Current CBSE/Class 12/Science/Physics/Unit 3-Magnetic Effect of Current & Magnetism Exam Coaching/NEET-UG Coaching +2 Exam Coaching/Engineering Entrance Coaching/IIT JEE Coaching/IIT JEE Foundation Course Exam Coaching/Engineering Entrance Coaching/IIT JEE Coaching/IIT JEE Mains Coaching less

Magnetic effects of Current Numerical Solving

Institute of Conceptual Physics

Finding Physics Too Tough ? We can make it simple for you. Majority of Science Students suffer because...

It is just a sample. Will post some more examples.Magnetic Effects of Current numerical are typically concerned with Biot Svart Law. The primary sources of confusion in these Numerical are:-1. The direction of magnetic Field. The current carrying conductors carry a Current and that Current produced a... read more

It is just a sample. Will post some more examples.
Magnetic Effects of Current numerical are typically concerned with Biot Svart Law. The primary sources of confusion in these Numerical are:-
1. The direction of magnetic Field. The current carrying conductors carry a Current and that Current produced a B whose direction should be carefully decided using Right Hand Thumb Rule. One must understand the Right Hand Thumb Rule Carefully.
2. Please also note that Biot Savart Law Requires one to be smart in applying Integral Calculus. Because the shape of the current carrying conductor can be anything. Generally, we get numerical on Circular Loop, Square Loop. Straight Conductors of infinite length which are very easy,
3. Application of vectors. Since we have to finally find the Resultant of B ( Magnetic field due to multiple sources of B ), the knowledge of vectors needs to be very good. So reread vectors.
4. The angle between dl vector and the r vector. Dl points in the direction of current and r vector points in the course of the point where the Field is desired. Dl→">.

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Lesson Posted on 15 Jun CBSE/Class 11/Science/Physics Exam Coaching/NEET-UG Coaching Exam Coaching/Engineering Entrance Coaching/IIT JEE Coaching/IIT JEE Foundation Course +1 Exam Coaching/Engineering Entrance Coaching/IIT JEE Coaching/IIT JEE Mains Coaching less

Useful Collision Concepts Two dimensional Collision

Institute of Conceptual Physics

Finding Physics Too Tough ? We can make it simple for you. Majority of Science Students suffer because...

We should note the following concepts when solving a Two-Body Collision Numerical:-Distance Between the centres of two Bodies -"b."When we have two objects colliding with each other, we assume both are in the same straight line, i.e. the centre of both the objects are precisely on the same straight line.... read more

We should note the following concepts when solving a Two-Body Collision Numerical:-
Distance Between the centres of two Bodies -"b."
When we have two objects colliding with each other, we assume both are in the same straight line, i.e. the centre of both the objects are precisely on the same straight line. These Collisions are Called Head-On Collisions.  But that may not be the case always. In reality, we still have a Collision in which there exists a distance between the centre of lines of two bodies. This distance is called the Impact Parameter.
Scattering Angles
After the collision, both the bodies move along different angles called scattering angles.
Explosion Collision
If there is an explosion during the collision, the overall Kinetic Energy increase, but the linear Momentum remains constant.
Perfectly Inelastic Collisions
If the two colliding bodies Stick together after Collision, we say its a Perfectly Inelastic Collision. The maximum loss of Kinetic Energy happens. Kinetic Energy gets lost in the form of Sound and Heat.

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Answered on 03 Jun Exam Coaching/Engineering Entrance Coaching/IIT JEE Coaching

Krunal M

Tutor

R1 =2 R2 =5 R2-R1=3>0 So there is only one tangent is possible
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Answered on 21 Apr Exam Coaching/Engineering Entrance Coaching/IIT JEE Coaching

Kousik Manna

Chemistry Tutor

It depends on you.
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Lesson Posted on 26/03/2018 CBSE/Class 12/Science/Mathematics CBSE/Class 11 CBSE/Class 10/Mathematics/UNIT III: Coordinate Geometry/Coordinate geometry/Class 10 Difference between two points and section formula +7 Tuition/Class XI-XII Tuition (PUC) Exam Coaching/Engineering Entrance Coaching/IIT JEE Coaching Exam Coaching/Engineering Entrance Coaching/IIT JEE Coaching/IIT JEE Advanced Coaching Exam Coaching/Engineering Entrance Coaching/IIT JEE Coaching/IIT JEE Crash Course Exam Coaching/Engineering Entrance Coaching/IIT JEE Coaching/IIT JEE Foundation Course Exam Coaching/Engineering Entrance Coaching/IIT JEE Coaching/IIT JEE Integrated Coaching Exam Coaching/Engineering Entrance Coaching/IIT JEE Coaching/IIT JEE Mains Coaching less

Class 11th - Maths

GOODWILL GATE2IIT

Calculate slope of a line(AB) formed by joining the co-ordinates A(-3, 5) and B(4,8)
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Lesson Posted on 24/06/2017 Exam Coaching/Foreign Education Exam Coaching/GRE Coaching Exam Coaching/Foreign Education Exam Coaching/GMAT Coaching Exam Coaching/Foreign Education Exam Coaching/SAT Coaching +2 Exam Coaching/Engineering Entrance Coaching/IIT JEE Coaching Exam Coaching/Engineering Entrance Coaching/IIT JEE Coaching/IIT JEE Advanced Coaching less

How To Determine If Points Are Collinear In Coordinate Geometry?

Ravi kota

I am a Pro-active, responsible and result-oriented Math trainer with a strong passion for student improvement...

How to prove if points are Collinear in coordinate geometry? Collinear points definition: Three or more points that lie on a same straight line are called collinear points. Consider a straight line L in the above Cartesian coordinate plane formed by x axis and y axis. This straight line L is... read more

How to prove if points are Collinear in coordinate geometry? 

 Collinear points definition:

  • Three or more points that lie on a same straight line are called collinear points.
  • Consider a straight line L in the above Cartesian coordinate plane formed by x axis and y axis.
  • This straight line L is passing through three points A, B and C whose coordinates are (2, 4), (4, 6) and (6, 8) respectively.
  • {We may also say, alternatively, that the three points A (2, 4), B (4, 6) and C (6, 8)are lying on a same straight line L}
  • Three or more points which lie on a same straight line are called collinear points.

How to find if three points are collinear?:

  • There are two methods to find if three points are collinear.
  • One is slope formula method and the other is area of triangle method.
  • Slope formula method to find that points are collinear.
  • Three or more points are collinear, if slope of any two pairs of points is same.
  • With three points A, B and C, three pairs of points can be formed, they are: AB, BC and AC.
  • If Slope of AB = slope of BC = slope of AC, then A, B and C are collinear points.

Example

Show that the three points A (2, 4), B (4, 6) and C (6, 8) are collinear.

Solution:

  • If the three points A (2, 4), B (4, 6) and C (6, 8) are collinear, then
  • slopes of any two pairs of points will be equal.
  • Now, apply slope formula to find the slopes of the respective pairs of points:
  • Slope of AB = (6 – 4)/ (4 – 2) = 1,
  • Slope of BC = (8 – 6)/ (6 – 4) = 1, and
  • Slope of AC = (8 – 4) /(6 – 2) = 1
  • Since slopes of any two pairs out of three pairs of points are same, this proves that A, B and C are collinear points.
  • Area of triangle to find if three points are collinear.
  • Three points are collinear if the value of area of triangle formed by the three points is zero.
  • Apply the coordinates of the given three points in the area of triangle formula. If the result for area is zero, then the given points are said to be collinear.
  • First of all, recall the formula for area of a triangle formed by three points.

It is

                                                                 

In the formula above, the two vertical bars enclosing the variables represent a determinant.

Let us apply the coordinates of the above three points A, B and C in the determinant formula above for area of a triangle to check if the answer is zero.

Since the result for area of triangle is zero, therefore A (2, 4), B (4, 6) and C (6, 8) are collinear points.

 

 

 

 

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