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Answered on 15 Feb CBSE/Class 10/Mathematics

Monu Kumar

Mathematics Tutor

If u describe the something with patience, ability to manage the any subject with confidence and if u followed innovative new ways of teaching and many other things then your future in this field is the great successful
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Lesson Posted 2 days ago CBSE/Class 10/Mathematics

Circular Motions & typical Time Speed & Distance

Sujoy D.

1. Strong concept building classes. 2. Weekly tests in weak areas for students to improve their confidence. 3....

QUESTION If a man cycles at 10 km/hr, then he arrives at a certain place at 1 p.m. If he cycles at 15 km/hr, he will arrive at the same place at 11a.m. At what speed must he cycle to get there at noon? 1) 11 km/hr 2) 12 km/hr 3) 13 km/hr 4) 14 km/hr* ANSWER ANS : 2*10*15/25 = 60/5 = 12 since the times... read more

QUESTION

If a man cycles at 10 km/hr, then he arrives at a certain place at 1 p.m. If he cycles at 15 km/hr, he will arrive at the same place at 11a.m. At what speed must he cycle to get there at noon?

1) 11 km/hr
2) 12 km/hr
3) 13 km/hr
4) 14 km/hr*

 

ANSWER

ANS : 2*10*15/25 = 60/5 = 12

since the times are 1pm,12 pm , 11 pm are in AP , speeds should be in HP. for 12 PM ==> HM(10,15) = 2*10*15 /(10+15) = 12.

 

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Lesson Posted 2 days ago CBSE/Class 10/Mathematics

MAXIMA & MINIMA

Sujoy D.

1. Strong concept building classes. 2. Weekly tests in weak areas for students to improve their confidence. 3....

QUESTION If (x, y, z) is an ordered triplet such that 6x + 5y + 2z = 53, where x, y and z are positive integers, then what is the difference between maximum and minimum value of x + y + z? ANSWER OA=13 , 6x+5y+2z=53 to maximize the value ..maximize z as much as possible bcz that will give u max value... read more

QUESTION

If (x, y, z) is an ordered triplet such that 6x + 5y + 2z = 53, where x, y and z are positive integers, then what is the difference between maximum and minimum value of
x + y + z?

 

ANSWER

OA=13 , 6x+5y+2z=53

to maximize the value ..maximize z as much as possible bcz that will give u max value of x+y+z
means minimize x and y

so x=1 and y=1

so 6+5+2z=53 so z=21

now for min value maximize x as max as possible

so x=6 and y=3 and z=1 so 23-10=13

 

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Answered on 14 Feb CBSE/Class 10/Mathematics Tuition/Class IX-X Tuition

Had Ravita scored 10 more marks in her Mathematics test out of 30 marks, 9 times these marks would have... read more
Had Ravita scored 10 more marks in her Mathematics test out of 30 marks, 9 times these marks would have been the square of her actual marks. How many marks did she get in the test? read less

Basanti D.

Math Magician

Got X mark , then 9(X+10)= X2(X square) . OR X^2 - 9X - 90 =0 ,OR (X – 15)(X + 6) =0 ,OR X = 15 , OR Ravita got 15 mark Answer .
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Answered on 14 Feb CBSE/Class 10/Mathematics Tuition/Class IX-X Tuition

A motor boat whose speed is 18 km/h in still water takes 1 hour more to go 24 km upstream than to return... read more
A motor boat whose speed is 18 km/h in still water takes 1 hour more to go 24 km upstream than to return downstream to the same spot. Find the speed of the stream. read less

Basanti D.

Math Magician

Boat speed in Still water 18km/hour. So boat speed in down stream =( 18+X) km/hour ,boat speed in up stream =(18 -X)km/hour. Time in up stream – time in down stream =1 hour. Now 24/(18-X) - 1 =24/ (18+X) . OR solving the equation—X2 +48X -18×18 =0 , OR (X-6)(X+54) OR ... read more

Boat speed in Still water 18km/hour. So boat speed in down stream =( 18+X) km/hour  ,boat speed in up stream =(18 -X)km/hour. Time in up stream – time in down stream =1 hour.  Now  24/(18-X)   - 1  =24/ (18+X)  .

OR    solving the equation—X2 +48X -18×18 =0  , OR   (X-6)(X+54)  OR   X=6 km/hour speed of stream                        

Boat speed in Still water 18km/hour. So boat speed in down stream =( 18+X) km/hour  ,boat speed in up stream =(18 -X)km/hour. Time in up stream – time in down stream =1 hour.  Now  24/(18-X)   - 1  =24/ (18+X)  .

OR    solving the equation—X2 +48X -18×18 =0  , OR   (X-6)(X+54)  OR   X=6 km/hour speed of stream                        

Boat speed in Still water 18km/hour. So boat speed in down stream =( 18+X) km/hour  ,boat speed in up stream =(18 -X)km/hour. Time in up stream – time in down stream =1 hour.  Now  24/(18-X)   - 1  =24/ (18+X)  .

OR    solving the equation—X2 +48X -18×18 =0  , OR   (X-6)(X+54)  OR   X=6 km/hour speed of stream                        

Boat speed in Still water 18km/hour. So boat speed in down stream =( 18+X) km/hour  ,boat speed in up stream =(18 -X)km/hour. Time in up stream – time in down stream =1 hour.  Now  24/(18-X)   - 1  =24/ (18+X)  .

OR    solving the equation—X2 +48X -18×18 =0  , OR   (X-6)(X+54)  OR   X=6 km/hour speed of stream                        

Boat speed in Still water 18km/hour. So boat speed in down stream =( 18+X) km/hour  ,boat speed in up stream =(18 -X)km/hour. Time in up stream – time in down stream =1 hour.  Now  24/(18-X)   - 1  =24/ (18+X)  .

OR    solving the equation—X2 +48X -18×18 =0  , OR   (X-6)(X+54)  OR   X=6 km/hour speed of stream                        

Boat speed in Still water 18km/hour. So boat speed in down stream =( 18+X) km/hour  ,boat speed in up stream =(18 -X)km/hour. Time in up stream – time in down stream =1 hour.  Now  24/(18-X)   - 1  =24/ (18+X)  .

OR    solving the equation—X2 +48X -18×18 =0  , OR   (X-6)(X+54)  OR   X=6 km/hour speed of stream                        

Boat speed in Still water 18km/hour. So boat speed in down stream =( 18+X) km/hour  ,boat speed in up stream =(18 -X)km/hour. Time in up stream – time in down stream =1 hour.  Now  24/(18-X)   - 1  =24/ (18+X)  .

OR    solving the equation—X2 +48X -18×18 =0  , OR   (X-6)(X+54)  OR   X=6 km/hour speed of stream                        

Boat speed in Still water 18km/hour. So boat speed in down stream =( 18+X) km/hour  ,boat speed in up stream =(18 -X)km/hour. Time in up stream – time in down stream =1 hour.  Now  24/(18-X)   - 1  =24/ (18+X)  .

OR    solving the equation—X2 +48X -18×18 =0  , OR   (X-6)(X+54)  OR   X=6 km/hour speed of stream                        

Boat speed in Still water 18km/hour. So boat speed in down stream =( 18+X) km/hour  ,boat speed in up stream =(18 -X)km/hour. Time in up stream – time in down stream =1 hour.  Now  24/(18-X)   - 1  =24/ (18+X)  .

OR    solving the equation—X2 +48X -18×18 =0  , OR   (X-6)(X+54)  OR   X=6 km/hour speed of stream                        

Boat speed in Still water 18km/hour. So boat speed in down stream =( 18+X) km/hour  ,boat speed in up stream =(18 -X)km/hour. Time in up stream – time in down stream =1 hour.  Now  24/(18-X)   - 1  =24/ (18+X)  .

OR    solving the equation—X2 +48X -18×18 =0  , OR   (X-6)(X+54)  OR   X=6 km/hour speed of stream                        

Boat speed in Still water 18km/hour. So boat speed in down stream =( 18+X) km/hour  ,boat speed in up stream =(18 -X)km/hour. Time in up stream – time in down stream =1 hour.  Now  24/(18-X)   - 1  =24/ (18+X)  .

OR    solving the equation—X2 +48X -18×18 =0  , OR   (X-6)(X+54)  OR   X=6 km/hour speed of stream                        

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Answered on 14 Feb CBSE/Class 10/Mathematics Tuition/Class IX-X Tuition

In a class test, the sum of marks obtained by P in Mathematics and Science is 28. Had he got 3 more marks... read more
In a class test, the sum of marks obtained by P in Mathematics and Science is 28. Had he got 3 more marks in Mathematics and 4 marks less in Science, the product of marks obtained in the two subjects would have been 180? Find the marks obtained in two subjects separately. read less

Basanti D.

Math Magician

P got (X) mark in math , (28 – X) mark in science , So (X+3)((28 – X – 4) =180 .OR (X +3)( 24 – X) =180 . OR 21X – X^2 +72 = 180, OR 180 – 72 – 21X + X^2 = 0 OR 108 – 21X + X^2 = 0 . OR (X -12)(X – 9) =0 . P got... read more

P    got      (X) mark in math ,    (28 – X)  mark in science ,  So  (X+3)((28 – X – 4)  =180  .OR  (X +3)( 24 – X) =180 .  OR  21X – X^2 +72 = 180, OR  180 – 72 – 21X + X^2  = 0  OR   108 – 21X + X^2 = 0 .     OR  (X -12)(X – 9)  =0  .

   P   got mark(  MATH  =9 ,science =19)  OR (MATH= 12,Science = 16) ANSWER  .

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Answered 2 days ago CBSE/Class 10/Mathematics Tuition/Class IX-X Tuition

A motor boat whose speed is 18 km/h in still water takes 1 hour more to go 24 km upstream than to return... read more
A motor boat whose speed is 18 km/h in still water takes 1 hour more to go 24 km upstream than to return downstream to the same spot. Find the speed of the stream. read less

Vivekanand Chaudhary

Maths Tutor

Let's speed of stream in x KMPH. Use formula Time= Distance/Speed. 24/(18-x)=24/(18+x)+1, Which gives a quadratic equation, x²+48x-324=0. After solving this we get x= 6. Hence stream speed is 6 KMPH.
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Answered on 11 Feb CBSE/Class 10/Mathematics Tuition/Class IX-X Tuition

Vishal Sharma

?
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Answered on 08 Jan CBSE/Class 10/Mathematics Tuition/Class IX-X Tuition

In a class test, the sum of marks obtained by P in Mathematics and Science is 28. Had he got 3 more marks... read more
In a class test, the sum of marks obtained by P in Mathematics and Science is 28. Had he got 3 more marks in Mathematics and 4 marks less in Science, the product of marks obtained in the two subjects would have been 180? Find the marks obtained in two subjects separately. read less

Chandresh K R

Tutor

Answer:- (Maths=12, Science=16) or (Maths=9, Science=19). Explaination:- Let the marks in mathematics be X Then marks in science = 28 - x (according to the first condition) Now according to second condition; (X + 3) x [(28 - x) - 4 ] =180 then on solving, we get; X = 12 or X = 9 Therefore, The marks... read more

Answer:- (Maths=12, Science=16) or (Maths=9, Science=19).

Explaination:-

Let the marks in mathematics be X

Then marks in science = 28 - x (according to  the first condition)

Now according to second condition;

(X + 3) x [(28 - x) - 4 ] =180

then on solving, we get;   X = 12 or X = 9

Therefore, 

The marks in mathematics and science (respectively) will be 12 & 16 or 9 & 19.

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Answered on 13 Feb CBSE/Class 10/Mathematics Tuition/Class IX-X Tuition

Prove that x2 ? x is divisible by 2 for all positive integer x.

Nagineni Deva Prasad

The expression x^2-x always gives even number for any integer , so that it always divisible by 2
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