Rupesh Kumar

Kundli, Sonipat, India - 131028

Rupesh Kumar photo

Rupesh Kumar

Chemistry

Kundli, Sonipat, India- 131028.

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Overview

Studied from vibrant academy, kota.
Secured AIR-5773 rank in IIT Jee. due to my keen interest in teaching specially chemistry, I would like to teach chemistry in a way that I get and understand so that someone secure better rank in iit or any national level competitive exam.

Languages Spoken

English

Education

National institute of food technology entrepreneurship and management, kundli, sonipat, haryana Pursuing

Bachelor of Technology (B.Tech.)

Address

Kundli, Sonipat, India - 131028

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Engineering Entrance Coaching classes Overview

Engineering Entrance Coaching classes

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Engineering Entrance Exams

BITSAT Coaching Classes, GATE Coaching Classes, IIT JEE Coaching Classes

IITJEE Coaching

IIT JEE Advanced Coaching, IIT JEE Mains Coaching, IIT JEE Foundation Course, IIT JEE Integrated Coaching, IIT JEE Crash Course

Type of class

Regular Classes, Crash Course

IIT-JEE Subjects

Chemistry

Reviews

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Answers by Rupesh Kumar (1)

Answered on 07/01/2018 CBSE/Class 12/Science/Physics Tuition/Class XI-XII Tuition (PUC)

Electrons are emitted from the cathode of a photocell of negligible work function, when photons of wavelength... ...more
Electrons are emitted from the cathode of a photocell of negligible work function, when photons of wavelength are incident on it. Derive the expression for the de Broglie wavelength of the electrons emitted in terms of the wavelength of the incident light.

E=Φ+K.E max. Where: Φ=work function of electrode Given: Φ=0 ∴ E=K.E of electron where: E= incident energy. λ=h÷p. Where: h= plank cons. P= momentum K.E = (1÷2)mv* *=2 p= mv ∴ p=√2mK.E. Now put value in de- Broglie wavelength formula we get,... ...more

E=Φ+K.E max.

Where: Φ=work function of electrode

Given: Φ=0

∴ E=K.E of electron where: E= incident energy.

λ=h÷p.

Where: h= plank cons.

P= momentum

K.E = (1÷2)mv*    *=2

p= mv 

∴ p=√2mK.E.

Now put value in de- Broglie wavelength formula we get, 

λ = h÷√2mK.E required and.

Where:λ= de Broglie wavelength

 K.E= kinetic energy of electron.

Answers 2 Comments
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Rupesh KumarDirections

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Engineering Entrance Coaching classes

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Engineering Entrance Exams

BITSAT Coaching Classes, GATE Coaching Classes, IIT JEE Coaching Classes

IITJEE Coaching

IIT JEE Advanced Coaching, IIT JEE Mains Coaching, IIT JEE Foundation Course, IIT JEE Integrated Coaching, IIT JEE Crash Course

Type of class

Regular Classes, Crash Course

IIT-JEE Subjects

Chemistry

Class 11 Tuition

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 11 Tuition

1

Board

CBSE

CBSE Subjects taught

Mathematics, Chemistry

Taught in School or College

No

Class 12 Tuition

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 12 Tuition

1

Board

CBSE

CBSE Subjects taught

Mathematics, Chemistry

Taught in School or College

No

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No Reviews yet! Be the first one to Review

Answers by Rupesh Kumar (1)

Answered on 07/01/2018 CBSE/Class 12/Science/Physics Tuition/Class XI-XII Tuition (PUC)

Electrons are emitted from the cathode of a photocell of negligible work function, when photons of wavelength... ...more
Electrons are emitted from the cathode of a photocell of negligible work function, when photons of wavelength are incident on it. Derive the expression for the de Broglie wavelength of the electrons emitted in terms of the wavelength of the incident light.

E=Φ+K.E max. Where: Φ=work function of electrode Given: Φ=0 ∴ E=K.E of electron where: E= incident energy. λ=h÷p. Where: h= plank cons. P= momentum K.E = (1÷2)mv* *=2 p= mv ∴ p=√2mK.E. Now put value in de- Broglie wavelength formula we get,... ...more

E=Φ+K.E max.

Where: Φ=work function of electrode

Given: Φ=0

∴ E=K.E of electron where: E= incident energy.

λ=h÷p.

Where: h= plank cons.

P= momentum

K.E = (1÷2)mv*    *=2

p= mv 

∴ p=√2mK.E.

Now put value in de- Broglie wavelength formula we get, 

λ = h÷√2mK.E required and.

Where:λ= de Broglie wavelength

 K.E= kinetic energy of electron.

Answers 2 Comments
Dislike Bookmark

Rupesh Kumar describes himself as Chemistry. He conducts classes in Class 11 Tuition, Class 12 Tuition and Engineering Entrance Coaching. Rupesh is located in Kundli, Sonipat. Rupesh takes at students Home and Regular Classes- at his Home. He has 1 years of teaching experience . Rupesh is pursuing Bachelor of Technology (B.Tech.) from National institute of food technology entrepreneurship and management, kundli, sonipat , haryana. HeĀ is well versed in English.

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