What is the smallest five-digit number that, when divided by 7, 11, and 21, leaves a remainder of 5 in each case?

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Ramakant Reddy

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the no will be of the form lcm(7,11,21)k+5 that is 1617k+5 i.e 11324
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Take those three numbers and find their LCM(Least common multiple) . So LCM of 7, 11 and 21 is 231. Now required number = 231*x+5 Here find the value of x such that it gives you a numbe just above 10000. If x=43 then number becomes 9938 which is a 4 digit number so discard it. Take x=44 and...
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Take those three numbers and find their LCM(Least common multiple) . So LCM of 7, 11 and 21 is 231. Now required number = 231*x+5 Here find the value of x such that it gives you a numbe just above 10000. If x=43 then number becomes 9938 which is a 4 digit number so discard it. Take x=44 and then you get a number as 10169. Now divide it by 7,11 and 21 and all you get as remainder will be 5 always. read less
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