What is the remainder of 1x1! +2x2! +3x3! +…+100x100! When divided by 202? (2! =2factorial=2x1)

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Rewrite the terms: (2-1)*1!+(3-1)*2!+..........+(101-1)*100!= 101!-1! When this is divided by 202, the remainder is -1, which implies the remainder is 201.
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