Ambi Road, Pune 
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D Y Patil institute of engineering and technology Pursuing
BE electrical
Ambi Road, Pune, India - 410507
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Class Location
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Years of Experience in Class 12 Tuition
1
Board
CBSE, State
Subjects taught
Physics, Mathematics
Taught in School or College
No
Answered on 15/10/2019 Learn CBSE - Class 12/Physics/Unit 1-Electrostatics/ELECTROSTATIC POTENTIAL AND CAPACITANCE/NCERT Solutions/Exercise 2
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The given figure shows six equal amount of charges, q, at the vertices of a regular hexagon.
Where, Charge, q = 5 µC = 5 × 10- 6 C
Side of the hexagon, l = AB = BC = CD = DE = EF = FA = 10 cm
Distance of each vertex from centre O, d = 10 cm
Electric potential at point O,
Where,
= Permittivity of free space
Therefore, the potential at the centre of the hexagon is 2.7 × 106 V.
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Answers 6 
Comments Answered on 15/10/2019 Learn CBSE - Class 12/Physics/Unit 1-Electrostatics/ELECTROSTATIC POTENTIAL AND CAPACITANCE/NCERT Solutions/Exercise 2
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CASE 1
There are two charges,
Distance between the two charges, d = 16 cm = 0.16 m
Consider a point P on the line joining the two charges, as shown in the given figure.
r = Distance of point P from charge q1
Let the electric potential (V) at point P be zero.
Potential at point P is the sum of potentials caused by charges q1 and q2 respectively.
Where,
= Permittivity of free space
For V = 0, equation (i) reduces to
Therefore, the potential is zero at a distance of 10 cm from the positive charge between the charges
CASE 2
Suppose point P is outside the system of two charges at a distance s from the negative charge, where potential is zero,
as shown in the following figure.
For this arrangement, potential is given by,
For V = 0, equation (ii) reduces to
Therefore, the potential is zero at a distance of 40 cm from the positive charge outside the system of charges.
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Class Location
Online Classes (Video Call via UrbanPro LIVE)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
1
Board
CBSE, State
Subjects taught
Physics, Mathematics
Taught in School or College
No
Answered on 15/10/2019 Learn CBSE - Class 12/Physics/Unit 1-Electrostatics/ELECTROSTATIC POTENTIAL AND CAPACITANCE/NCERT Solutions/Exercise 2
Ask a Question
Post a Lesson
The given figure shows six equal amount of charges, q, at the vertices of a regular hexagon.
Where, Charge, q = 5 µC = 5 × 10- 6 C
Side of the hexagon, l = AB = BC = CD = DE = EF = FA = 10 cm
Distance of each vertex from centre O, d = 10 cm
Electric potential at point O,
Where,
= Permittivity of free space
Therefore, the potential at the centre of the hexagon is 2.7 × 106 V.
Like 0 Answers 6 Comments Answered on 15/10/2019 Learn CBSE - Class 12/Physics/Unit 1-Electrostatics/ELECTROSTATIC POTENTIAL AND CAPACITANCE/NCERT Solutions/Exercise 2
Ask a Question
Post a Lesson
CASE 1
There are two charges,
Distance between the two charges, d = 16 cm = 0.16 m
Consider a point P on the line joining the two charges, as shown in the given figure.
r = Distance of point P from charge q1
Let the electric potential (V) at point P be zero.
Potential at point P is the sum of potentials caused by charges q1 and q2 respectively.
Where, = Permittivity of free space
For V = 0, equation (i) reduces to
Therefore, the potential is zero at a distance of 10 cm from the positive charge between the charges
CASE 2
Suppose point P is outside the system of two charges at a distance s from the negative charge, where potential is zero,
as shown in the following figure.
For this arrangement, potential is given by,
For V = 0, equation (ii) reduces to
Therefore, the potential is zero at a distance of 40 cm from the positive charge outside the system of charges.
Like 0 Answers 7 Comments Ask a Question
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