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Asked by Anurag Last Modified
Sadika
To determine the value of xx such that 42x542x5 is a multiple of 9, we can sum the digits of the number and see if the result is a multiple of 9.
The number 42x542x5 can be written as 420+10x+5420+10x+5.
Now, let's consider the sum of the digits:
4+2+0+1+0+x+5=12+x4+2+0+1+0+x+5=12+x
For the entire number to be divisible by 9, the sum 12+x12+x must be a multiple of 9.
To find the value of xx, we need to find a digit such that 12+x12+x is divisible by 9.
Let's try different values of xx from 0 to 9:
So, x=3x=3 is the value that makes 42x542x5 a multiple of 9.
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