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If
then
is equal to
A. ![]()
B. ![]()
C. ![]()
D. ![]()
![]()

Hence, the correct answer is D.
Integrate the functions


Equating the coefficients of x2, x, and constant term, we obtain
−A + B − C = 0
B + C = 0
A = 1
On solving these equations, we obtain
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From equation (1), we obtain

Integrate the functions

Integrate the functions
[Hint: Put
]

Integrate the functions

Integrate the functions


On dividing, we obtain

Integrate the functions

Equating the coefficients of x2, x, and constant term, we obtain
A + B = 0
B + C = 5
9A + C = 0
On solving these equations, we obtain
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From equation (1), we obtain

Integrate the functions
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Let x − a = t ⇒ dx = dt

Integrate the functions

Integrate the functions
![]()
Let sin x = t ⇒ cos x dx = dt

Integrate the functions

Integrate the functions

Integrate the functions
![]()
Let x4 = t ⇒ 4x3dx = dt

Integrate the functions

Let ex = t ⇒ exdx = dt

Integrate the functions

Equating the coefficients of x3, x2, x, and constant term, we obtain
A + C = 0
B + D = 0
4A + C = 0
4B + D = 1
On solving these equations, we obtain
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From equation (1), we obtain

Integrate the functions
= cos3x × sin x
Let cos x = t ⇒ −sin x dx = dt

Integrate the functions

Integrate the functions

Integrate the functions

Integrate the functions



Integrate the functions

Integrate the functions

Equating the coefficients of x2, x,and constant term, we obtain
A + C = 1
3A + B + 2C = 1
2A + 2B + C = 1
On solving these equations, we obtain
A = −2, B = 1, and C = 3
From equation (1), we obtain

Integrate the functions

Integrate the functions

Integrating by parts, we obtain


Evaluate the definite integrals



Evaluate the definite integrals

When x = 0, t = 0 and ![]()

Evaluate the definite integrals

When
and when![]()

Evaluate the definite integrals

When
and when 

As
, therefore,
is an even function.
It is known that if f(x) is an even function, then ![]()

Evaluate the definite integrals

Evaluate the definite integrals

Evaluate the definite integrals

From equation (1), we obtain
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Evaluate the definite integrals
![]()

Adding (1) and (2), we obtain

Evaluate the definite integrals




From equations (1), (2), (3), and (4), we obtain
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Evaluate the definite integrals
![]()

Equating the coefficients of x2, x, and constant term, we obtain
A + C = 0
A + B = 0
B = 1
On solving these equations, we obtain
A = −1, C = 1, and B = 1

![]()
Hence, the given result is proved.
Evaluate the definite integrals
![]()
Integrating by parts, we obtain

Hence, the given result is proved.
Evaluate the definite integrals

Therefore, f (x) is an odd function.
It is known that if f(x) is an odd function, then ![]()
![]()
Hence, the given result is proved.
Evaluate the definite integrals

Hence, the given result is proved.
Evaluate the definite integrals


Hence, the given result is proved.
Evaluate the definite integrals

Integrating by parts, we obtain

Let 1 − x2 = t ⇒ −2x dx = dt

Hence, the given result is proved.
Evaluate
as a limit of a sum.
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It is known that,






is equal to
A. ![]()
B. ![]()
C. ![]()
D.

Hence, the correct answer is A.
is equal to
A. ![]()
B. ![]()
C. ![]()
D.
#new_question#
If
then
is equal to
A. ![]()
B. ![]()
C. ![]()
D.

Hence, the correct answer is B.
The value of
is
A. 1
B. 0
C. − 1
D. ![]()


Adding (1) and (2), we obtain

Hence, the correct answer is B.
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