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 [Hint: Put ex = t]
 [Hint: Put ex = t]

Let ex = t ⇒ exdx = dt


Substituting t = 1 and t = 0 in equation (1), we obtain
A = −1 and B = 1


Integrate the rational functions
 
 
Let 

Substituting x = 1, 2, and 3 respectively in equation (1), we obtain 

Integrate the rational functions
 
  Let 

Equating the coefficients of x2, x, and constant term, we obtain
A + C = 0
−A + B = 1
−B + C = 0
On solving these equations, we obtain

From equation (1), we obtain

Integrate the rational functions
 
 
Let 

Equating the coefficients of x and constant term, we obtain
A + B = 1
2A + B = 0
On solving, we obtain
A = −1 and B = 2

Integrate the rational functions
 
 
Let 

Equating the coefficients of x and constant term, we obtain
A + B = 0
−3A + 3B = 1
On solving, we obtain


Integrate the rational functions
 
 
Let 

On solving
A = 1, B = -5, C = 4

Integrate the rational functions
 
 
Let 

Substituting x = −1 and −2 in equation (1), we obtain
A = −2 and B = 4

Integrate the rational functions
 
 
It can be seen that the given integrand is not a proper fraction.
Therefore, on dividing (1 − x2) by x(1 − 2x), we obtain

Let 

Substituting x = 0 and  in equation (1), we obtain
 in equation (1), we obtain
A = 2 and B = 3

Substituting in equation (1), we obtain

Integrate the rational functions
 
 
Let 

Equating the coefficients of x2, x, and constant term, we obtain
A + C = 0
−A + B = 1
−B + C = 0
On solving these equations, we obtain

From equation (1), we obtain

Integrate the rational functions
 
 

Let 

Substituting x = 1 in equation (1), we obtain
B = 4
Equating the coefficients of x2 and x, we obtain
A + C = 0
B − 2C = 3
On solving, we obtain


Integrate the rational functions
 
 

Let 

Equating the coefficients of x2 and x, we obtain


Integrate the rational functions
 
 

Let 

Substituting x = −1, −2, and 2 respectively in equation (1), we obtain


Integrate the rational functions
 
 
It can be seen that the given integrand is not a proper fraction.
Therefore, on dividing (x3 + x + 1) by x2 − 1, we obtain

Let 

Substituting x = 1 and −1 in equation (1), we obtain


Integrate the rational functions
 
 

Equating the coefficient of x2, x, and constant term, we obtain
A − B = 0
B − C = 0
A + C = 2
On solving these equations, we obtain
A = 1, B = 1, and C = 1

Integrate the rational functions
 
 

Equating the coefficient of x and constant term, we obtain
A = 3
2A + B = −1 ⇒ B = −7

Integrate the rational functions
 
 


Equating the coefficient of x3, x2, x, and constant term, we obtain

On solving these equations, we obtain



A. 
B. 
C. 
D.  
 

Substituting x = 1 and 2 in (1), we obtain
A = −1 and B = 2

Hence, the correct answer is B.

A. 
B. 
C. 
D. 

Equating the coefficients of x2, x, and constant term, we obtain
A + B = 0
C = 0
A = 1
On solving these equations, we obtain
A = 1, B = −1, and C = 0

Hence, the correct answer is A.
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