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 Differentiate w.r.t. x the function  
 

Differentiate w.r.t. x the function  
 
Using chain rule, we obtain

 Differentiate w.r.t. x the function 
 

Taking logarithm on both the sides, we obtain

Differentiating both sides with respect to x, we obtain

 Differentiate w.r.t. x the function  
 

Using chain rule, we obtain

 Differentiate w.r.t. x the function 
 

 Differentiate w.r.t. x the function  
 

Taking logarithm on both the sides, we obtain

Differentiating both sides with respect to x, we obtain

  Differentiate w.r.t. x the function  , for some constant a and b.
, for some constant a and b. 

By using chain rule, we obtain

 Differentiate w.r.t. x the function  
 

Taking logarithm on both the sides, we obtain

Differentiating both sides with respect to x, we obtain

Differentiate w.r.t. x the function
 , for some fixed
, for some fixed  and
and  
 


Differentiating both sides with respect to x, we obtain


Differentiating both sides with respect to x, we obtain

s = aa
Since a is constant, aa is also a constant.
∴
From (1), (2), (3), (4), and (5), we obtain

 Differentiate w.r.t. x the function  , for
, for  
 

Differentiating both sides with respect to x, we obtain

Differentiating with respect to x, we obtain

Also,

Differentiating both sides with respect to x, we obtain

Substituting the expressions of  in equation (1), we obtain
in equation (1), we obtain

Find , if
, if  
 

 Find , if
, if  
 

If , for, −1 < x <1, prove that
, for, −1 < x <1, prove that
 
 
It is given that,


Differentiating both sides with respect to x, we obtain

Hence, proved.
If , for some
, for some  prove that
 prove that
 is a constant independent of a and b.
is a constant independent of a and b. 
It is given that,
Differentiating both sides with respect to x, we obtain


Hence, proved.
 If  with
 with  prove that
prove that 
 

Then, equation (1) reduces to.png)
⇒sin(a+y−y)  
Hence, proved.
 If  and
and , find
, find  
 


If , show that
, show that  exists for all real x, and find it.
exists for all real x, and find it.
It is known that, 
Therefore, when x ≥ 0, 
In this case,  and hence,
 and hence, 
When x < 0, 
In this case,  and hence,
 and hence, 
Thus, for ,
,  exists for all real x and is given by,
exists for all real x and is given by,

Using mathematical induction prove that  for all positive integers n.
for all positive integers n. 

For n = 1,

∴P(n) is true for n = 1
Let P(k) is true for some positive integer k.
That is, 
It has to be proved that P(k + 1) is also true.

Thus, P(k + 1) is true whenever P (k) is true.
Therefore, by the principle of mathematical induction, the statement P(n) is true for every positive integer n.
Hence, proved.
Using the fact that sin (A + B) = sin A cos B + cos A sin B and the differentiation, obtain the sum formula for cosines.

Differentiating both sides with respect to x, we obtain

Does there exist a function which is continuos everywhere but not differentiable at exactly two points? Justify your answer ?

.png)
It can be seen from the above graph that, the given function is continuos everywhere but not differentiable at exactly two points which are 0 and 1.
 If , prove that
, prove that  
 

Thus, 
 If , show that
, show that 
It is given that,


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