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Differentiate the function with respect to x.
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Taking logarithm on both the sides, we obtain

Differentiating both sides with respect to x, we obtain

Differentiate the function with respect to x.

Taking logarithm on both the sides, we obtain

Differentiating both sides with respect to x, we obtain

Differentiate the function with respect to x.
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Taking logarithm on both the sides, we obtain
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Differentiating both sides with respect to x, we obtain

Differentiate the function with respect to x.

u = xx
Taking logarithm on both the sides, we obtain
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Differentiating both sides with respect to x, we obtain

v = 2sin x
Taking logarithm on both the sides with respect to x, we obtain
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Differentiating both sides with respect to x, we obtain

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Differentiate the function with respect to x.
![]()
Taking logarithm on both the sides, we obtain

Differentiating both sides with respect to x, we obtain

Differentiate the function with respect to x.


Differentiating both sides with respect to x, we obtain


Differentiating both sides with respect to x, we obtain

Therefore, from (1), (2), and (3), we obtain

Differentiate the function with respect to x.

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u = (log x)x

Differentiating both sides with respect to x, we obtain

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Differentiating both sides with respect to x, we obtain

Therefore, from (1), (2), and (3), we obtain
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Differentiate the function with respect to x.


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Differentiating both sides with respect to x, we obtain

Therefore, from (1), (2), and (3), we obtain
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Differentiate the function with respect to x.


Differentiating both sides with respect to x, we obtain


Differentiating both sides with respect to x, we obtain

From (1), (2), and (3), we obtain
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Differentiate the function with respect to x.


Differentiating both sides with respect to x, we obtain


Differentiating both sides with respect to x, we obtain

From (1), (2), and (3), we obtain

Differentiate the function with respect to x.


Differentiating both sides with respect to x, we obtain


Differentiating both sides with respect to x, we obtain

From (1), (2), and (3), we obtain

Find
of function.
The given function is![]()
Let xy = u and yx = v
Then, the function becomes u + v = 1
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Differentiating both sides with respect to x, we obtain


Differentiating both sides with respect to x, we obtain

From (1), (2), and (3), we obtain

Find
of function.
Take log both sides and differentiate both sides.
That is xlogy=ylogx
X/y.dy/dx+logy=y.1/x+logx.dy/dx
dy/dx(x/y-logx)=1/x-logy
dy/dx=(1/x-logy)/(x/y-logx)
dy/dx=y(1-xlogy)/x(x-ylogx)
Find
of function.
The given function is![]()
Taking logarithm on both the sides, we obtain
![]()
Differentiating both sides, we obtain

Find
of function.
The given function is![]()
Taking logarithm on both the sides, we obtain

Differentiating both sides with respect to x, we obtain

Find the derivative of the function given by
and hence find
.
The given relationship is![]()
Taking logarithm on both the sides, we obtain
![]()
Differentiating both sides with respect to x, we obtain

Differentiate
in three ways mentioned below
(i) By using product rule.
(ii) By expanding the product to obtain a single polynomial.
(iii By logarithmic differentiation.
Do they all give the same answer?
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(i)

(ii)

(iii) ![]()
Taking logarithm on both the sides, we obtain
![]()
Differentiating both sides with respect to x, we obtain


From the above three observations, it can be concluded that all the results of
are same.
If u, v and w are functions of x, then show that
![]()
in two ways-first by repeated application of product rule, second by logarithmic differentiation.
Let ![]()
By applying product rule, we obtain

By taking logarithm on both sides of the equation
, we obtain
![]()
Differentiating both sides with respect to x, we obtain

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