Sujay Sahu

Airoli, Mumbai, India - 400708

Sujay Sahu photo

Sujay Sahu

Maths Magacian

Airoli, Mumbai, India- 400708.

3.9
UrbanPro Rating

Details verified of Sujay Sahu

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Education

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Overview

1.Good concept in Maths from school onwards.secured very good marks in all classess.
2.recieved regional maths olympiad certificate and many maths maths olympiad certidicate in all classes.
3.90 percentile in maths in Btech.
3.taught many students. Improved their basic concepts which help them achieved very good marks in their board exams.
4.able to provide a good quality learning in maths and shortcuts for competative exams.

Languages Spoken

Hindi

English

Education

Nit Trichy 2017

Master of Engineering - Master of Technology (M.E./M.Tech.)

Address

Airoli, Mumbai, India - 400708

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Class 6 Tuition Overview

Class 6 Tuition

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 6 Tuition

4

Board

State, ICSE, CBSE

CBSE Subjects taught

Mathematics

ICSE Subjects taught

Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Mathematics

Reviews

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Answers by Sujay Sahu (5)

Answered on 27/02/2018 CBSE/Class 9/Mathematics Tuition/Class IX-X Tuition

Perpendicular on base of isoceles triangle bisect the third side. So using pythagoras we get height = 3 cm Now area of triangle= 1/2 *height *base =1/2*8*3=12 sq cm
Answers 5 Comments
Dislike Bookmark

Answered on 27/02/2018 CBSE/Class 9/Mathematics Tuition/Class IX-X Tuition

Perpendicular on base of isoceles triangle bisect the third side. So using pythagoras we get height = 3 cm Now area of triangle= 1/2 *height *base =1/2*8*3=12 sq cm
Answers 5 Comments
Dislike Bookmark

Answered on 27/02/2018 CBSE/Class 9/Mathematics Tuition/Class IX-X Tuition

Perpendicular on base of isoceles triangle bisect the third side. So using pythagoras we get height = 3 cm Now area of triangle= 1/2 *height *base =1/2*8*3=12 sq cm
Answers 5 Comments
Dislike Bookmark

Answered on 27/02/2018 CBSE/Class 9/Science Tuition/Class IX-X Tuition

An electric heater of 2000 Walt is working for 5 hours. How much energy it consume?

Energy=power*time =2000*5*3600 =36 MJ
Answers 2 Comments
Dislike Bookmark

Answered on 27/02/2018 CBSE/Class 9/Science Tuition/Class IX-X Tuition

An electric heater of 2000 Walt is working for 5 hours. How much energy it consume?

Energy=power*time =2000*5*3600 =36 MJ
Answers 2 Comments
Dislike Bookmark

Sujay SahuDirections

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Class 6 Tuition 3.9

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 6 Tuition

4

Board

State, ICSE, CBSE

CBSE Subjects taught

Mathematics

ICSE Subjects taught

Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Mathematics

Class 7 Tuition 3.9

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 7 Tuition

4

Board

State, ICSE, CBSE

CBSE Subjects taught

Mathematics

ICSE Subjects taught

Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Mathematics

Class 8 Tuition 3.9

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 8 Tuition

4

Board

State, ICSE, CBSE

CBSE Subjects taught

Mathematics

ICSE Subjects taught

Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Mathematics

Class 9 Tuition 3.9

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 9 Tuition

4

Board

CBSE, ICSE, State

CBSE Subjects taught

Mathematics

ICSE Subjects taught

Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Mathematics

Class 10 Tuition 3.9

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 10 Tuition

4

Board

CBSE, ICSE, State

CBSE Subjects taught

Mathematics

ICSE Subjects taught

Mathematics

Taught in School or College

No

State Syllabus Subjects taught

Mathematics

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No Reviews yet! Be the first one to Review

Answers by Sujay Sahu (5)

Answered on 27/02/2018 CBSE/Class 9/Mathematics Tuition/Class IX-X Tuition

Perpendicular on base of isoceles triangle bisect the third side. So using pythagoras we get height = 3 cm Now area of triangle= 1/2 *height *base =1/2*8*3=12 sq cm
Answers 5 Comments
Dislike Bookmark

Answered on 27/02/2018 CBSE/Class 9/Mathematics Tuition/Class IX-X Tuition

Perpendicular on base of isoceles triangle bisect the third side. So using pythagoras we get height = 3 cm Now area of triangle= 1/2 *height *base =1/2*8*3=12 sq cm
Answers 5 Comments
Dislike Bookmark

Answered on 27/02/2018 CBSE/Class 9/Mathematics Tuition/Class IX-X Tuition

Perpendicular on base of isoceles triangle bisect the third side. So using pythagoras we get height = 3 cm Now area of triangle= 1/2 *height *base =1/2*8*3=12 sq cm
Answers 5 Comments
Dislike Bookmark

Answered on 27/02/2018 CBSE/Class 9/Science Tuition/Class IX-X Tuition

An electric heater of 2000 Walt is working for 5 hours. How much energy it consume?

Energy=power*time =2000*5*3600 =36 MJ
Answers 2 Comments
Dislike Bookmark

Answered on 27/02/2018 CBSE/Class 9/Science Tuition/Class IX-X Tuition

An electric heater of 2000 Walt is working for 5 hours. How much energy it consume?

Energy=power*time =2000*5*3600 =36 MJ
Answers 2 Comments
Dislike Bookmark

Sujay Sahu describes himself as Maths Magacian. He conducts classes in Class 10 Tuition, Class 6 Tuition and Class 7 Tuition. Sujay is located in Airoli, Mumbai. Sujay takes at students Home and Regular Classes- at his Home. He has 4 years of teaching experience . Sujay has completed Master of Engineering - Master of Technology (M.E./M.Tech.) from Nit Trichy in 2017. HeĀ is well versed in Hindi and English.

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