Rithani, Meerut Details verified of Vikash Sharma✕
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Mahamaya Technical University, Noida (formerly AKTU, LUCKNOW) 2013
Master of Computer Applications (M.C.A.)
Rithani, Meerut, India - 250103
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Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
7
Board
International Baccalaureate, ISC/ICSE, IGCSE, CBSE
Experience in School or College
6 Years 6 Month Experience with school of repute
Subjects taught
Mathematics, Computer Science, Information Technology
Taught in School or College
Yes
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
7
Board
IGCSE, ICSE, International Baccalaureate, CBSE
Experience in School or College
6.6 Years in school of repute
Subjects taught
Computer Application, Computers, Mathematics, Information Technology, Information and Comunication Technology, Computer Practices
Taught in School or College
Yes
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 11 Tuition
7
Board
International Baccalaureate, ISC/ICSE, IGCSE, CBSE
Experience in School or College
6.6 Years from school of repute
Subjects taught
Computer Science, Information Technology, Mathematics
Taught in School or College
Yes
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class I-V Tuition
7
Board
CBSE, Cambridge Assessment International Education (CAIE), International Baccalaureate, ICSE
Experience in School or College
6.6 years in reputed CBSE ICSE SCHOOL
Subjects taught
Computer Science, Computers, Mathematics, Science
Taught in School or College
Yes
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Computer Classes
7
Type of Computer course taken
Software Programming, Training in Software application usage, Training in Computer tools usage, Basics of Computer usage
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in C++ Language Classes
7
Proficiency level taught
Basic C++, Advanced C++
Answered on 24/06/2019
Ask a Question
Post a Lesson
It can be done so simply by looking forward to the algebric identity...
By taking RHS to another side..
It will become
X^2+Y^2+Z^2-(XY+YZ+ZX)=0
To make it identity we will multiply both side with (X+Y+Z)
Hence
(X+Y+Z)(X^2+Y^2+Z^2-(XY+YZ+ZX))=0×(X+Y+Z)...... (1)
We know that
X^3+Y^3+Z^3-3XYZ=(X+Y+Z)(X^2+Y^2+Z^2-(XY+YZ+ZX))........(2)
Therefore by substituting this in equation
(X+Y+Z)(X^2+Y^2+Z^2-(XY+YZ+ZX))=0 as(0×(X+Y+Z)=0)
Hence
X^3+Y^3+Z^3-3XYZ=0 .......from eq 2
Hence
X^3+Y^3+Z^3=3XYZ
Proved
Like 0 
Answers 278 
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Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
7
Board
International Baccalaureate, ISC/ICSE, IGCSE, CBSE
Experience in School or College
6 Years 6 Month Experience with school of repute
Subjects taught
Mathematics, Computer Science, Information Technology
Taught in School or College
Yes
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
7
Board
IGCSE, ICSE, International Baccalaureate, CBSE
Experience in School or College
6.6 Years in school of repute
Subjects taught
Computer Application, Computers, Mathematics, Information Technology, Information and Comunication Technology, Computer Practices
Taught in School or College
Yes
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 11 Tuition
7
Board
International Baccalaureate, ISC/ICSE, IGCSE, CBSE
Experience in School or College
6.6 Years from school of repute
Subjects taught
Computer Science, Information Technology, Mathematics
Taught in School or College
Yes
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class I-V Tuition
7
Board
CBSE, Cambridge Assessment International Education (CAIE), International Baccalaureate, ICSE
Experience in School or College
6.6 years in reputed CBSE ICSE SCHOOL
Subjects taught
Computer Science, Computers, Mathematics, Science
Taught in School or College
Yes
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Computer Classes
7
Type of Computer course taken
Software Programming, Training in Software application usage, Training in Computer tools usage, Basics of Computer usage
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in C++ Language Classes
7
Proficiency level taught
Basic C++, Advanced C++
Answered on 24/06/2019
Ask a Question
Post a Lesson
It can be done so simply by looking forward to the algebric identity...
By taking RHS to another side..
It will become
X^2+Y^2+Z^2-(XY+YZ+ZX)=0
To make it identity we will multiply both side with (X+Y+Z)
Hence
(X+Y+Z)(X^2+Y^2+Z^2-(XY+YZ+ZX))=0×(X+Y+Z)...... (1)
We know that
X^3+Y^3+Z^3-3XYZ=(X+Y+Z)(X^2+Y^2+Z^2-(XY+YZ+ZX))........(2)
Therefore by substituting this in equation
(X+Y+Z)(X^2+Y^2+Z^2-(XY+YZ+ZX))=0 as(0×(X+Y+Z)=0)
Hence
X^3+Y^3+Z^3-3XYZ=0 .......from eq 2
Hence
X^3+Y^3+Z^3=3XYZ
Proved
Like 0 Answers 278 Comments Ask a Question
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