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1)3/13,2)4/13

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First of all the question should read " a letter" is drawn rather than "a word" is drawn. Now probability of any event E is given by P(E) = n(E)/n(S). where n(E) represents the number of elements of even E and n(S) represents the number of elements in the sample space S. Thus, Answer to Question (1)...

read more First of all the question should read " a letter" is drawn rather than "a word" is drawn. Now probability of any event E is given by P(E) = n(E)/n(S). where n(E) represents the number of elements of even E and n(S) represents the number of elements in the sample space S. Thus, Answer to Question (1) is 3/13 as n(S) = number of letters in ASSASSINATION= 13 and n(E) = number of A's in ASSASSINATION = 3. Similarly, answer to question (2) is 4/13 as n(S) =13 and n(E) = number of S's = 4. read less

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1) 3/13 AND 2) 4/13

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First of all look at the word and find out howmany A and S we have in the word ASSASSINATION. We have 3 A and 4 S. Therefore 1) the probability of picking up A is 3/13 where 13 is the total number of letters in the word. 2) the probability of picking up S is 4/13.

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Ans is 3/13.total no of A is 3 and total letter are there is 13 so according to rule probability to getting letter A is 3/13

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Probability of getting A is 3/13 and probability of getting s is 4/13

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Answer will be 3/13 and 4/13 As we have Total: 13 letters Out of which we have 3 'A' and 4 'B'.

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