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Answered on 06 Apr Learn Unit 1-Electrostatics

Sadika

Electrostatic field lines do not form closed loops because if they did, it would imply that there are no sources or sinks of electric field within the region enclosed by the loop, which violates the Gauss's law for electric fields.
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Answered on 06 Apr Learn Unit 1-Electrostatics

Sadika

Electric field lines never cross each other because if they did, it would imply that at the point of intersection, there are multiple directions of electric field, which is not physically possible. The direction of the electric field at any point must be unique and well-defined. read more

 

  • Electric field lines never cross each other because if they did, it would imply that at the point of intersection, there are multiple directions of electric field, which is not physically possible. The direction of the electric field at any point must be unique and well-defined.

 

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Answered on 06 Apr Learn Unit 1-Electrostatics

Sadika

The electrostatic field at the surface of a charge must be perpendicular at every point because if it had a component parallel to the surface, it would cause charges to move along the surface, which would violate the condition of electrostatic equilibrium. read more

 

  • The electrostatic field at the surface of a charge must be perpendicular at every point because if it had a component parallel to the surface, it would cause charges to move along the surface, which would violate the condition of electrostatic equilibrium.

 

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Answered on 06 Apr Learn Unit 1-Electrostatics

Sadika

Two conclusions from the given scenario where electric field intensity is zero at point P between two point charges: The magnitudes of the two charges must be equal. The charges must have opposite signs.
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Answered on 06 Apr Learn Unit 1-Electrostatics

Sadika

The dipole moment of an electric dipole is defined as the product of the magnitude of one of the charges (q) and the distance (2a) between the charges, where a is the distance from the center of the dipole to each charge. It is a vector quantity.
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Answered on 06 Apr Learn Unit 1-Electrostatics

Sadika

A proton placed in a uniform electric field directed along the positive X-axis will tend to move in the direction opposite to the field, i.e., along the negative X-axis, due to the force exerted on it by the electric field.
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Answered on 06 Apr Learn Unit 1-Electrostatics

Sadika

In a uniform electric field, a dipole placed with its axis perpendicular to the field lines is in stable equilibrium. Conversely, if the dipole is placed with its axis parallel to the field lines, it is in unstable equilibrium.
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Answered on 06 Apr Learn Unit 1-Electrostatics

Sadika

If the point charges experience a force of 8 N in air, the force experienced by them when held in water at the same distance will be the same, as the force between charges depends only on the magnitude of the charges and the distance between them, not on the medium.
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Answered on 06 Apr Learn Unit 1-Electrostatics

Sadika

If the point charges experience a force of 8 N in air, the force experienced by them when held in water at the same distance will be the same, as the force between charges depends only on the magnitude of the charges and the distance between them, not on the medium.
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Answered on 06 Apr Learn Unit 1-Electrostatics

Sadika

In the scenario of a metallic sphere placed in a uniform electric field, the electric field lines follow a path that is perpendicular to the surface of the sphere. This is because charges on the surface of a conductor redistribute themselves such that the electric field inside the conductor is zero and... read more

In the scenario of a metallic sphere placed in a uniform electric field, the electric field lines follow a path that is perpendicular to the surface of the sphere. This is because charges on the surface of a conductor redistribute themselves such that the electric field inside the conductor is zero and the electric field lines terminate perpendicular to the surface.

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