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Lines (In two-dimensions)

Lines (In two-dimensions) relates to CBSE/Class 10/Mathematics/UNIT III: Coordinate Geometry

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Lines (In two-dimensions) Questions

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Answered on 16/04/2024 Learn CBSE/Class 10/Mathematics/UNIT III: Coordinate Geometry/Lines (In two-dimensions)

Sadika

To find the area of triangle read more

To find the area of triangle

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Answered on 16/04/2024 Learn CBSE/Class 10/Mathematics/UNIT III: Coordinate Geometry/Lines (In two-dimensions)

Sadika

To find the ratio in which the point read more

To find the ratio in which the point

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Answered on 16/04/2024 Learn CBSE/Class 10/Mathematics/UNIT III: Coordinate Geometry/Lines (In two-dimensions)

Sadika

To find the area of the quadrilateral ABCD , you can use the shoelace formula. First, list the coordinates of the vertices in clockwise order: read more

To find the area of the quadrilateral ABCD , you can use the shoelace formula. First, list the coordinates of the vertices in clockwise order:

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Answered on 16/04/2024 Learn CBSE/Class 10/Mathematics/UNIT III: Coordinate Geometry/Lines (In two-dimensions)

Sadika

To find the coordinates of point read more

To find the coordinates of point

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Answered on 12/03/2022 Learn CBSE/Class 10/Mathematics/UNIT III: Coordinate Geometry/Lines (In two-dimensions)

Shailesh Kaushik

youtube @shaileshkaushik to have a look at my teaching method.

Let's assume the coordinates of other end are (x1,y1). Now, we know that centre is the mid point of diameter ends. So we can use mid point formula here as follows: -2 = (x1+2)/2 and 5 = (y1+3)/2 => -4 = x1 + 2 and 10 = y1 + 3 => x1 = -4-2 and y1 = 10 -3 => x1 = -6 ... read more

Let's assume the coordinates of other end are (x1,y1).

Now, we know that centre is the mid point of diameter ends. So we can use mid point formula here as follows:

-2 = (x1+2)/2 and 5 = (y1+3)/2

=> -4  = x1 + 2      and  10 = y1 + 3

=> x1 = -4-2          and  y1  = 10 -3

=> x1 = -6             and  y1 = 7

So the coordinates of the other end of diameter are (-6,7)

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