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Post a LessonAnswered on 23 Feb Learn Introduction To Graphs
Nazia Khanum
Solution: Finding Coordinates of Intercepts for a Line
Given Points:
Finding Slope (m):
Using Point-Slope Form:
Solving for y-intercept (x = 0):
Solving for x-intercept (y = 0):
Summary:
This concludes the solution for finding the coordinates of the points where the line intersects the x-axis and y-axis.
Answered on 23 Feb Learn Introduction To Graphs
Nazia Khanum
Line Passing through (2,3) and (3,2) - Coordinates of Intercepts
Formula for Slope (m): m=y2−y1x2−x1m=x2−x1y2−y1
Given Points: P1(x1,y1)=(2,3)P1(x1,y1)=(2,3) P2(x2,y2)=(3,2)P2(x2,y2)=(3,2)
Calculation: m=2−33−2=−1m=3−22−3=−1
Point-Slope Form: y−y1=m⋅(x−x1)y−y1=m⋅(x−x1)
Substitute Values: y−3=−1⋅(x−2)y−3=−1⋅(x−2)
Simplify: y=−x+1y=−x+1
Definition: The x-intercept is where the line crosses the x-axis (y=0y=0).
Substitute y=0y=0 in the Equation: 0=−x+10=−x+1
Solve for x: x=1x=1
Coordinates of x-Intercept: (1,0)(1,0)
Definition: The y-intercept is where the line crosses the y-axis (x=0x=0).
Substitute x=0x=0 in the Equation: y=−0+1y=−0+1
Coordinates of y-Intercept: (0,1)(0,1)
Equation of the Line: y=−x+1y=−x+1
x-Intercept: (1,0)(1,0)
y-Intercept: (0,1)(0,1)
This completes the analysis of the line passing through the points (2,3) and (3,2) with the determination of the x and y intercepts.
Answered on 23 Feb Learn Introduction To Graphs
Nazia Khanum
Line Passing through (2,3) and (3,2) - Coordinates of Intercepts
Formula for Slope (m): m=y2−y1x2−x1m=x2−x1y2−y1
Given Points: P1(x1,y1)=(2,3)P1(x1,y1)=(2,3) P2(x2,y2)=(3,2)P2(x2,y2)=(3,2)
Calculation: m=2−33−2=−1m=3−22−3=−1
Point-Slope Form: y−y1=m⋅(x−x1)y−y1=m⋅(x−x1)
Substitute Values: y−3=−1⋅(x−2)y−3=−1⋅(x−2)
Simplify: y=−x+1y=−x+1
Definition: The x-intercept is where the line crosses the x-axis (y=0y=0).
Substitute y=0y=0 in the Equation: 0=−x+10=−x+1
Solve for x: x=1x=1
Coordinates of x-Intercept: (1,0)(1,0)
Definition: The y-intercept is where the line crosses the y-axis (x=0x=0).
Substitute x=0x=0 in the Equation: y=−0+1y=−0+1
Coordinates of y-Intercept: (0,1)(0,1)
Equation of the Line: y=−x+1y=−x+1
x-Intercept: (1,0)(1,0)
y-Intercept: (0,1)(0,1)
This completes the analysis of the line passing through the points (2,3) and (3,2) with the determination of the x and y intercepts.
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Answered on 23 Feb Learn Introduction To Graphs
Nazia Khanum
Verification of Points on a Line
Let's plot the given points on a coordinate plane.
These points are plotted on the y-axis where the x-coordinate is always 1.
We observe that all the points lie on a vertical line parallel to the y-axis.
The given points A, B, C, and D lie on a vertical line parallel to the y-axis.
The line passing through these points is a vertical line.
This concludes the verification process for the given points. If you have any further questions or need clarification, feel free to ask.
Answered on 24 Feb Learn Introduction To Graphs
Sadika
To plot the given points K(1,3)K(1,3), L(2,3)L(2,3), M(3,3)M(3,3), and N(4,3)N(4,3), we can plot them on a Cartesian coordinate system:
All these points lie on the line y=3y=3, which is a horizontal line passing through the y-coordinate 3. This line is commonly known as the horizontal line y=3y=3.
So, the points KK, LL, MM, and NN all lie on the horizontal line y=3y=3.
Asked on 10/01/2022 Learn Introduction To Graphs
Take Class 8 Tuition from the Best Tutors
Asked on 10/01/2022 Learn Introduction To Graphs
Asked on 10/01/2022 Learn Introduction To Graphs
Asked on 10/01/2022 Learn Introduction To Graphs
Take Class 8 Tuition from the Best Tutors
Asked on 10/01/2022 Learn Introduction To Graphs
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