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Post a LessonAnswered on 02/02/2024 Learn CBSE/Class 8/Maths/Exponents and Powers
Pooja R. Jain
To simplify the expression (1/32)3(1/32)3, you raise the base to the power of the exponent:
(1/32)3=13/323(1/32)3=13/323
13=113=1
323==32768
So,
(1/32)3=1/32768(1/32)3=1/32768
Therefore, (1/32)3(1/32)3 simplifies to 1/327681/32768.
Answered on 02/02/2024 Learn CBSE/Class 8/Maths/Exponents and Powers
Pooja R. Jain
To evaluate the expression (5−1×82)/(2−3×10−1)(5−1×82)/(2−3×10−1), follow the order of operations (PEMDAS/BODMAS):
Let's calculate step by step:
5−1×82=5−1×64=5−64=−595−1×82=5−1×64=5−64=−59
2−3×10−1=2−3×0.1=2−0.3=1.72−3×10−1=2−3×0.1=2−0.3=1.7
Now, substitute these results back into the original expression:
−591.71.7−59
Finally, divide −59−59 by 1.71.7:
−591.7≈−34.705882351.7−59≈−34.70588235
So, the value of the given expression is approximately −34.71−34.71.
Answered on 02/02/2024 Learn CBSE/Class 8/Maths/Exponents and Powers
Pooja R. Jain
To find the value of mm in the equation 6m6−3=656−36m=65, follow these steps:
Simplify the expression on the left side:
6m6−3=6m3=2m6−36m=36m=2m
Now, set up the equation:
2m=652m=65
Solve for mm:
m=652m=265
So, the value of mm for which 6m6−3=656−36m=65 is m=652m=265 or m=32.5m=32.5.
Answered on 02/02/2024 Learn CBSE/Class 8/Maths/Exponents and Powers
Pooja R. Jain
Let's simplify the expression step by step:
[(12−1)−(13−1)]−1[(21−1)−(31−1)]−1
First, perform the operations inside each set of parentheses:
[(12−1)−(13−1)]−1[(21−1)−(31−1)]−1
[(12−22)−(13−33)]−1[(21−22)−(31−33)]−1
[(−12)−(−23)]−1[(2−1)−(3−2)]−1
Now, combine the terms inside the brackets:
[−12+23]−1[2−1+32]−1
To add the fractions, find a common denominator, which is 6:
[−36+46]−1[6−3+64]−1
[16]−1[61]−1
Finally, take the reciprocal of 1661:
116=6611=6
Therefore, [(12−1)−(13−1)]−1=6[(21−1)−(31−1)]−1=6
Answered on 02/02/2024 Learn CBSE/Class 8/Maths/Exponents and Powers
Pooja R. Jain
To simplify (−3)5×(53)5(−3)5×(35)5, let's break it down step by step:
Evaluate (−3)5(−3)5:
(−3)5=−3×−3×−3×−3×−3=−243(−3)5=−3×−3×−3×−3×−3=−243
Evaluate (53)5(35)5:
(53)5=5535==3555=
Now, multiply the results:
(−243)×(−243)×
The 243243 in the numerator and denominator cancels out:
(−243)×=−243×3125(−243)×=−243×3125
Now, calculate the product:
−243×3125=−−243×3125=
Therefore, (−3)5×(53)5(−3)5×(35)5 simplifies to −]−]
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