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Class 9 Mathematics

Class 9 Mathematics relates to CBSE - Class 9

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Top Tutors who teach Class 9 Mathematics

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Deepashree Class 9 Tuition trainer in Bangalore Featured
Basaveshwara Nagar, Bangalore
Top Tutor
12 yrs of Exp
500per hour
Classes: Class 9 Tuition, Spoken English and more.

I have working experience of 2 years teaching for 8th and 9th

2
Megha A. Class 9 Tuition trainer in Lucknow Featured
LDA Colony, Lucknow
8 yrs of Exp
300per hour
Classes: Class 9 Tuition, Class 7 Tuition and more.

The experience of teaching Maths to grade 9 is wonderful. Most of the students have a s phobia of Maths. Removing that phobia with my techniques and...

3
Vigneshwaran Class 9 Tuition trainer in Chennai Featured
Sholinganallur, Chennai
Verified
6 yrs of Exp
550per hour
Classes: Class 9 Tuition, Class 8 Tuition and more.

With 6 years of teaching experience in both home and online tutoring, I have developed a deep understanding of how to adapt my teaching methods to...

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Rehabari, Gmc
Verified
4 yrs of Exp
400per hour
Classes: Class 9 Tuition, Class 8 Tuition and more.

With 4+ years of experience, I specialize in teaching Class 9 students Science, English, and Social Studies in a way that makes tough topics simple...

5
Daulah, Sohna
4 yrs of Exp
Classes: Class 9 Tuition, Class 12 Tuition and more.

I have experience teaching class 9 students, focusing on building a strong academic foundation in subjects like Mathematics, Science, and English....

6
Hemant Kumar Class 9 Tuition trainer in Delhi Featured
Nangloi, Delhi
Verified
15 yrs of Exp
400per hour
Classes: Class 9 Tuition, Class 10 Tuition and more.

I have taught hundreds of students of class 9th so far from various boards such as CBSE, ICSE and state boards. I am also running my own coaching...

7
Urmelalagian, Urmelazhagian
2 yrs of Exp
300per hour
Classes: Class 9 Tuition

Iam a engineering student.iam giving online tuition since mathamatics, chemistry, home science. Iam completed in schooling in amali girls hr sec school...

8
Abhishek Lodha Class 9 Tuition trainer in Bangalore Featured
Jayanagar RBI Extension, Bangalore
Verified
18 yrs of Exp
1000per hour
Classes: Class 9 Tuition, Class 6 Tuition and more.

I am passionate about helping those who struggle with understanding Maths and Science. I firmly believe in conceptual learning and strive for my students...

9
Venkatesh G. Class 9 Tuition trainer in Hyderabad Featured
Narayanguda, Hyderabad
Verified
10 yrs of Exp
450per hour
Classes: Class 9 Tuition, Class I-V Tuition and more.

I have been working as a full time tutor since 2007. I can teach Mathematics, Physics, Chemistry and Computers(Basics) for the classes VII to XII....

10
Santhosh Gupta Jami Class 9 Tuition trainer in Hyderabad Featured
Yousufguda, Hyderabad
Verified
3 yrs of Exp
800per hour
Classes: Class 9 Tuition, Meditation and more.

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Class 9 Mathematics Questions

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Answered on 19 Jul Learn CBSE - Class 9/Class 9 Mathematics/Chapter 2 Polynomials/EXERCISE - 2.3

Parneet

Experienced Maths Tutor . MSc Mathematics. 3 + year experience.

i) 12 x^2 -4x-3x +1 = 4x(3x-1) - (3x-1) =(4x-1)(3x-1) ii) 2x^2 +6x +x+3 = 2x( x+3) + 1(x+3) = (2x+1)(x+3) iii) 6x^2 +9x - 4x -6 = 3x(2x+3) -2(2x+3)= (2x+3)(3x-2) iv) 3x^2 -4x+3x -4 =x(3x-4) +1(3x-4) =(3x-4)(x+1)
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Answered on 11 Jul Learn CBSE - Class 9/Class 9 Mathematics/Chapter 2 Polynomials/EXERCISE - 2.2

Rinsha V P

1)-5 2)5 3)-5÷2 4)2÷3 5)0 6)0 7)-d÷c
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Answered on 11 Aug Learn CBSE - Class 9/Class 9 Mathematics/Chapter 2 Polynomials/EXERCISE - 2.3

Sanjeev Verma

if x - 1 is a factor of a polynomial p(x) then by remainder theorem p(1) (value of the polynomial at x = 1) must be 0. and p(1) = $1^2 + 1 + k = 0$ so 1 + 1 + k = 0 that is 2 + k = 0 k = -2 is the answer
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Answered on 31 Jul Learn CBSE - Class 9/Class 9 Mathematics/Chapter 2 Polynomials/EXERCISE - 2.3

Satyansh Singh

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Answered on 11 Aug Learn CBSE - Class 9/Class 9 Mathematics/Chapter 2 Polynomials/EXERCISE - 2.4

Sanjeev Verma

in this question we will use the identity (ax + b) * (cx + d) = ac*x^2 + (ad + bc)* x + bd (1) (x + 4) (x + 10) = x^2 + (4 + 10)*x + 4 * 10 =x^2 + 14x + 40 (2) (x +8) (x - 10) = x^2 + (8 - 10)x + 8 * -10 = x^2 - 2x - 80 (3)(3x + 4) (3x -... read more

in this question we will use the identity 

(ax + b) * (cx + d) = ac*x^2 + (ad + bc)* x + bd

(1) (x + 4) (x + 10) = x^2 + (4 + 10)*x + 4 * 10

                               =x^2 + 14x + 40

(2) (x +8) (x - 10) = x^2 + (8 - 10)x + 8 * -10

                             = x^2 - 2x - 80

(3)(3x + 4) (3x - 5) = (3x)^2 + (4*3 + (- 5)*3) * x + 4 * (-5)

                              = 9x^2 - 3x - 20

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