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Q4(ii):
Factorise :
(ii) $2x^2 + 7x + 3$
Solution :
Initial Setup & Theoretical Foundation
We are tasked with factorising the quadratic polynomial:
$P(x) = 2x^2 + 7x + 3$
To factorise a quadratic polynomial of the standard form $ax^2 + bx + c$, we employ the "Splitting the Middle Term" method (also known as the AC method). This technique relies on finding two integers, $p$ and $q$, that satisfy two specific conditions simultaneously:
- Sum Condition: $p + q = b$ [The coefficient of the middle term]
- Product Condition: $p \times q = a \times c$ [The product of the leading coefficient and the constant term]
Step 1: Identifying Coefficients for the AC Method
By comparing the given polynomial $2x^2 + 7x + 3$ with the standard quadratic form $ax^2 + bx + c$, we extract the following coefficients:
- Leading coefficient ($a$) = $2$
- Middle coefficient ($b$) = $7$
- Constant term ($c$) = $3$
Next, we calculate the target product ($ac$):
$a \times c = 2 \times 3 = 6$
Step 2: Determining the Splitting Factors
We must find two integers $p$ and $q$ such that:
$p + q = 7$
$p \times q = 6$
Let us systematically evaluate the factor pairs of $6$:
| Factor Pair ($p, q$) | Product ($p \times q$) | Sum ($p + q$) | Condition Met? |
|---|---|---|---|
| $2, 3$ | $6$ | $5$ | No |
| $6, 1$ | $6$ | $7$ | Yes |
The correct integers are $6$ and $1$.
Step 3: Rewriting the Polynomial
We substitute the middle term $7x$ with the sum of $6x$ and $1x$ [Per the distributive property, $7x = (6 + 1)x = 6x + x$]:
$2x^2 + 6x + x + 3$
Step 4: Factorisation by Grouping
We now group the four terms into two pairs to extract the Greatest Common Factor (GCF) from each pair:
$= (2x^2 + 6x) + (x + 3)$
Extracting the GCF from the first group: The terms $2x^2$ and $6x$ share a common factor of $2x$.
$2x(x + 3)$
Extracting the GCF from the second group: The terms $x$ and $3$ share no common factors other than $1$.
$+ 1(x + 3)$
Reassembling the expression yields:
$= 2x(x + 3) + 1(x + 3)$
Notice that the binomial $(x + 3)$ is now a common factor to both major terms. We factor out $(x + 3)$ [By the Distributive Property of Multiplication over Addition, $AB + CB = (A + C)B$]:
$= (x + 3)(2x + 1)$
Visual Representation: Area Model of Factorisation
The area model geometrically validates our algebraic factorisation. The total area of the rectangle represents the polynomial $2x^2 + 7x + 3$, while the side lengths represent the factors $(2x + 1)$ and $(x + 3)$.
Final Solution: The factorised form of the polynomial $2x^2 + 7x + 3$ is $(x + 3)(2x + 1)$.
More Questions from Class 9 Mathematics Polynomials EXERCISE 2.3
- Q1(i): Determine which of the following polynomials has $(x + 1)$ a factor : (i) $x^3 + x^2 + x + 1$
- Q1(ii): Determine which of the following polynomials has $(x + 1)$ a factor : (ii) $x^4 + x^3 + x^2 + x + 1$
- Q1(iii): Determine which of the following polynomials has $(x + 1)$ a factor : (iii) $x^4 + 3x^3 + 3x^2 + x + 1$
- Q1(iv): Determine which of the following polynomials has $(x + 1)$ a factor : (iv) $x^3 – x^2 – (2 + \sqrt{2})x + \sqrt{2}$
- Q2(i): Use the Factor Theorem to determine whether $g(x)$ is a factor of $p(x)$ in each of the following cases: (i) $p(x) = 2x^3 + x^2 – 2x – 1, g(x) = x + 1$
- Q2(ii): Use the Factor Theorem to determine whether $g(x)$ is a factor of $p(x)$ in each of the following cases: (ii) $p(x) = x^3 + 3x^2 + 3x + 1, g(x) = x + 2$
- Q2(iii): Use the Factor Theorem to determine whether $g(x)$ is a factor of $p(x)$ in each of the following cases: (iii) $p(x) = x^3 – 4x^2 + x + 6, g(x) = x – 3$
- Q3(i): Find the value of $k$, if $x – 1$ is a factor of $p(x)$ in each of the following cases: (i) $p(x) = x^2 + x + k$
- Q3(ii): Find the value of $k$, if $x – 1$ is a factor of $p(x)$ in each of the following cases: (ii) $p(x) = 2x^2 + kx + \sqrt{2}$
- Q3(iii): Find the value of $k$, if $x – 1$ is a factor of $p(x)$ in each of the following cases: (iii) $p(x) = kx^2 – \sqrt{2}x + 1$
- Q3(iv): Find the value of $k$, if $x – 1$ is a factor of $p(x)$ in each of the following cases: (iv) $p(x) = kx^2 – 3x + k$
- Q4(i): Factorise : (i) $12x^2 – 7x + 1$
- Q4(iii): Factorise : (iii) $6x^2 + 5x – 6$
- Q4(iv): Factorise : (iv) $3x^2 – x – 4$
- Q5(i): Factorise : (i) $x^3 – 2x^2 – x + 2$
- Q5(ii): Factorise : (ii) $x^3 – 3x^2 – 9x – 5$
- Q5(iii): Factorise : (iii) $x^3 + 13x^2 + 32x + 20$
- Q5(iv): Factorise : (iv) $2y^3 + y^2 – 2y – 1$
CBSE Solutions for Class 9 Mathematics Polynomials
Chapters in CBSE - Class 9 Mathematics
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