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Q4:
If a point $C$ lies between two points $A$ and $B$ such that $AC = BC$, then prove that $AC = \frac{1}{2}AB$. Explain by drawing the figure.

Solution :

Given Variables & Initial Setup

Let $A$, $B$, and $C$ be three points on a straight line such that $C$ lies between $A$ and $B$.

  • The position of points is defined as: $A - C - B$ [By order of points on a line].
  • It is given that $AC = BC$ [Given Condition].

Step 1: Establishing the Segment Addition Axiom

According to Euclid’s Common Notion 4: "Things which coincide with one another are equal to one another." In the context of line segments, if $C$ lies between $A$ and $B$, the sum of the parts equals the whole:

$AC + BC = AB$ [By Euclid's Axiom: The whole is greater than the part, and specifically, if a point $C$ lies between $A$ and $B$, then $AC + CB = AB$].

Step 2: Algebraic Substitution

Since we are given $AC = BC$, we can substitute $AC$ for $BC$ in the equation established in Step 1:

$AC + AC = AB$ [Substitution Property of Equality].

$2AC = AB$ [By arithmetic summation].

Step 3: Derivation of the Final Identity

To isolate $AC$, we divide both sides of the equation by 2:

$\frac{2AC}{2} = \frac{AB}{2}$ [By Euclid’s Common Notion 3: If equals are subtracted from equals, the remainders are equal; here applying the division axiom].

$AC = \frac{1}{2}AB$.

Visual Representation

A C B AC BC

The figure illustrates three collinear points where the distance $AC$ is equal to the distance $BC$. Since the total distance $AB$ is the sum of $AC$ and $BC$, and $AC = BC$, it is mathematically necessary that $AC$ is exactly one-half of the total length $AB$.

Final Solution: $AC = \frac{1}{2}AB$


More Questions from Class 9 Mathematics Introduction to Euclid’s Geometry EXERCISE 5.1


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