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Q1(v):

Which of the following statements are true and which are false? Give reasons for your answers. (v) In Fig. 5.9, if $AB = PQ$ and $PQ = XY$, then $AB = X

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Solution :

Analysis of the Geometric Statement

The provided statement asserts that if line segment $AB = PQ$ and $PQ = XY$, then $AB = XY$. To evaluate the validity of this statement, we must refer to the fundamental axioms defined by Euclid in his work The Elements.

Step 1: Identifying the Applicable Euclidean Axiom

Euclid's First Axiom (Common Notion 1) states: "Things which are equal to the same thing are equal to one another."

In the context of the given variables:

  • $AB = PQ$ (Given)
  • $XY = PQ$ (Given as $PQ = XY$, which is symmetric)

Step 2: Logical Derivation

Since both $AB$ and $XY$ are equivalent to the common magnitude $PQ$, we apply the principle of transitivity of equality. If $a = b$ and $b = c$, then $a = c$. [Per Euclid’s First Common Notion].

Visual Representation

A B P Q X Y Equal length Common magnitude Equal length

Step 3: Conclusion

The statement is True. Because the magnitudes $AB$, $PQ$, and $XY$ represent lengths of line segments on a Euclidean plane, they satisfy the transitive property of equality established in the first of Euclid’s Common Notions.

Final Solution: The statement is True, as things which are equal to the same thing are equal to one another [Euclid's First Common Notion].


More Questions from Class 9 Mathematics Introduction to Euclid’s Geometry EXERCISE 5.1


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