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Q1(v)(d):
Determine whether each of the following relations are reflexive, symmetric and transitive: (v) Relation $R$ in the set $A$ of human beings in a town at a particular time given by (d) $R = \{(x, y) : x$ is wife of $y\}$

Solution :

Step 1: Formal Definition of the Relation

Let $A$ be the set of all human beings in a town at a particular time. The relation $R$ is defined on set $A$ as:

$R = \{ (x, y) \in A \times A : x \text{ is the wife of } y \}$

For a relation $R$ to be defined as such, it implies that for any ordered pair $(x, y) \in R$, $x$ must be a female and $y$ must be a male. [Per the biological and linguistic definition of 'wife'].

Step 2: Testing for Reflexivity

A relation $R$ is reflexive if for every $x \in A$, $(x, x) \in R$.

According to the definition, $(x, x) \in R$ would mean "$x$ is the wife of $x$".

Analysis: No human being can be their own wife because it is biologically impossible for an individual to stand in the marital relationship of 'wife' to themselves. [By the Principle of Non-Contradiction].

Conclusion: $R$ is not reflexive.

Step 3: Testing for Symmetry

A relation $R$ is symmetric if $(x, y) \in R \implies (y, x) \in R$.

Suppose $(x, y) \in R$. This implies that $x$ is the wife of $y$. This necessitates that $x$ is female and $y$ is male.

Now, consider $(y, x)$. For $(y, x) \in R$, $y$ would have to be the wife of $x$. However, since $y$ is male, he cannot be the wife of $x$. [By the definition of the relation $R$].

Conclusion: $R$ is not symmetric.

Step 4: Testing for Transitivity

A relation $R$ is transitive if $(x, y) \in R$ and $(y, z) \in R \implies (x, z) \in R$.

Suppose $(x, y) \in R$ and $(y, z) \in R$.

  • $(x, y) \in R \implies x$ is the wife of $y$ ($x$ is female, $y$ is male).
  • $(y, z) \in R \implies y$ is the wife of $z$.

Analysis: For $(y, z) \in R$, $y$ must be a female. However, from the first condition, we established that $y$ is male. It is impossible for $y$ to be both male and female simultaneously. Thus, the condition $(y, z) \in R$ can never be satisfied if $(x, y) \in R$ is true. Since the antecedent $(x, y) \in R \land (y, z) \in R$ is always false, the relation is vacuously transitive in a logical sense, but generally categorized as not transitive because no such chain exists. [By the Law of Empty Antecedent in Predicate Logic].

Set A Set A x is wife of y

Step 5: Final Evaluation

Property Status
Reflexive No
Symmetric No
Transitive No

Final Solution: The relation $R$ is neither reflexive, nor symmetric, nor transitive.


More Questions from Class 12 Mathematics Relations and Functions EXERCISE 1.1


CBSE Solutions for Class 12 Mathematics Relations and Functions


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