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Q10(ii):
Give an example of a relation. Which is (ii) Transitive but neither reflexive nor symmetric.

Solution :

1. Definitions and Logical Requirements

To construct a relation $R$ on a set $A$ that is transitive but neither reflexive nor symmetric, we must satisfy the following logical conditions:

  • Transitive: If $(a, b) \in R$ and $(b, c) \in R$, then $(a, c) \in R$ must hold for all $a, b, c \in A$.
  • Not Reflexive: There must exist at least one element $x \in A$ such that $(x, x) \notin R$. [By definition of reflexivity].
  • Not Symmetric: There must exist at least one pair $(a, b) \in R$ such that $(b, a) \notin R$. [By definition of symmetry].

2. Constructing the Set and Relation

Let the set $A = \{1, 2, 3\}$. We define the relation $R$ as follows:

$R = \{ (1, 2) \}$

3. Verification of Logical Properties

Property Analysis Result
Reflexivity For $R$ to be reflexive, $(1, 1), (2, 2),$ and $(3, 3)$ must be in $R$. Since $(1, 1) \notin R$, the relation is not reflexive. Not Reflexive
Symmetry For $R$ to be symmetric, if $(1, 2) \in R$, then $(2, 1)$ must be in $R$. Since $(2, 1) \notin R$, the relation is not symmetric. Not Symmetric
Transitivity Transitivity requires: If $(a, b) \in R$ and $(b, c) \in R \implies (a, c) \in R$. Here, there is no pair $(b, c)$ such that $b=2$. Thus, the condition is vacuously true. Transitive

4. Visual Representation

1 2 3

5. Conclusion

The relation $R = \{ (1, 2) \}$ on the set $A = \{1, 2, 3\}$ satisfies all requested conditions: it contains no identity elements (not reflexive), does not contain the reverse mapping $(2, 1)$ (not symmetric), and the transitive condition is satisfied vacuously because there is no chain of length two.

Final Solution: The relation $R = \{ (1, 2) \}$ defined on the set $A = \{1, 2, 3\}$ is transitive but neither reflexive nor symmetric.


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