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Q2:
If a population growing exponentially double in size in 3 years, what is the intrinsic rate of increase (\(r\)) of the population?

Solution :

Given Variables & Initial Setup

In population ecology, when resources are unlimited, a population exhibits exponential growth. The integral form of the exponential growth equation is given by:

$$ N_t = N_0 e^{rt} $$

Where:

  • $N_t$ = Population density/size after time $t$
  • $N_0$ = Population density/size at time $t = 0$ (initial population)
  • $r$ = Intrinsic rate of natural increase (per capita growth rate)
  • $t$ = Time period (in years)
  • $e$ = The base of natural logarithms (Euler's number, $\approx 2.71828$)

Based on the problem statement, the population doubles in size in 3 years. Therefore, we can establish the following parameters:

  • $t = 3 \text{ years}$
  • $N_t = 2N_0$ [Because the population is exactly twice its original size]

Step 1: Setting up the Equation

We substitute the known parameters into the standard exponential growth model to solve for the unknown variable, $r$:

$$ 2N_0 = N_0 e^{r(3)} $$

By dividing both sides of the equation by $N_0$, we isolate the exponential term [Per the division property of equality]:

$$ 2 = e^{3r} $$

Graphical Representation of Exponential Doubling

The following dynamically calculated SVG illustrates the exponential curve of the population over time, highlighting the exact doubling point at $t = 3$.

N₀ 2N₀ 0 3 Doubling Time (t=3) Time (years) Population Size (N)

Step 2: Logarithmic Evaluation

To solve for $r$, which is located in the exponent, we apply the natural logarithm ($\ln$, log base $e$) to both sides of the equation. This utilizes the inverse property of exponential functions, where $\ln(e^x) = x$:

$$ \ln(2) = \ln(e^{3r}) $$

$$ \ln(2) = 3r $$

Now, isolate $r$ algebraically by dividing both sides by 3:

$$ r = \frac{\ln(2)}{3} $$

Step 3: Numerical Calculation

The natural logarithm of 2 is a fundamental constant in population genetics and radioactive decay modeling:

$$ \ln(2) \approx 0.6931 $$

Substitute this constant back into the equation:

$$ r = \frac{0.6931}{3} $$

$$ r \approx 0.23103... $$

Rounding to three decimal places (the standard precision in demographic ecology), we get:

$$ r = 0.231 \text{ year}^{-1} $$

If expressed as a percentage, the population is growing at an intrinsic rate of approximately $23.1\%$ per year.

Final Solution: The intrinsic rate of increase ($r$) of the population is approximately $0.231$ (or $23.1\%$) per year.


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