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Q7.28:

A disc rotating about its axis with angular speed $\omega_o$ is placed lightly (without any translational push) on a perfectly frictionless table. The radius of the disc is $R$. What are the linear velocities of the points A, B and C on the disc shown in Fig. 7.41? Will the disc roll in the direction indicated ?

Solution :

Step 1: Identifying the Kinematic State

The disc is placed on a perfectly frictionless surface.

  • Initial condition: The disc is rotating with an angular velocity $\omega_0$ about its central axis.
  • Translation state: Since the disc is placed "lightly" without a translational push, its initial center-of-mass velocity $v_{cm} = 0$.
  • Friction state: As the surface is perfectly frictionless, there is no tangential force $\vec{f}$ acting on the points of contact. [Per Newton’s First Law of Motion, in the absence of external forces, the translational velocity remains constant at zero].

Step 2: Calculating Linear Velocity of Points A, B, and C

The linear velocity $\vec{v}$ of any point on a rotating body is given by the vector relation: $\vec{v} = \vec{v}_{cm} + \vec{\omega} \times \vec{r}$ Since $\vec{v}_{cm} = 0$, the velocity is purely rotational: $v = \omega_0 r$.

O A B C
Point Position Vector ($r$) Linear Velocity ($v = \omega_0 r$)
A $R$ (at the top) $v_A = R\omega_0$ (perpendicular to radius)
B $R$ (at the edge) $v_B = R\omega_0$ (perpendicular to radius)
C $R$ (at the bottom) $v_C = R\omega_0$ (perpendicular to radius)

Step 3: Evaluating the Rolling Condition

For a disc to roll without slipping, the condition $v_{cm} = r\omega$ must be satisfied at the point of contact with the surface.

  • The point of contact (let's assume the disc is horizontal, point C is the contact point) has a velocity $v_C = R\omega_0$.
  • Since $v_C \neq 0$ and $v_{cm} = 0$, the condition for pure rolling ($v_{contact} = 0$) is violated.
  • Furthermore, rolling requires the presence of static friction to provide the necessary torque to decelerate rotation and accelerate translation. [Per the definition of Rolling Motion].

Step 4: Final Conclusion

Because the surface is frictionless, there is no force to change the translational state of the center of mass or to create the torque necessary to induce rolling. The disc will continue to rotate in place with angular velocity $\omega_0$ and will not exhibit translational motion.

Final Solution: The linear velocities are $v_A = v_B = v_C = R\omega_0$. The disc will not roll; it will simply spin about its fixed central axis without any translational displacement.


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