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Q6.2:
In the HCl molecule, the separation between the nuclei of the two atoms is about 1.27 Ã… (1 Ã… = (10^{-10}) m). Find the approximate location of the CM of the molecule, given that a chlorine atom is about 35.5 times as massive as a hydrogen atom and nearly all the mass of an atom is concentrated in its nucleus.

Solution :

Step 1: Establishing the Coordinate System and Parameters

To determine the center of mass (CM) of the HCl molecule, we define a one-dimensional coordinate system along the internuclear axis. Let the position of the Hydrogen nucleus ($H$) be at the origin $x_H = 0$. The Chlorine nucleus ($Cl$) is situated at distance $d = 1.27 \, \text{Ã…} = 1.27 \times 10^{-10} \, \text{m}$.

  • Mass of Hydrogen atom: $m_H = m$
  • Mass of Chlorine atom: $m_{Cl} = 35.5 \, m$
  • Position of Hydrogen: $x_H = 0$
  • Position of Chlorine: $x_{Cl} = 1.27 \times 10^{-10} \, \text{m}$

Step 2: Mathematical Formulation of Center of Mass

The position of the center of mass $X_{CM}$ for a system of two point masses $m_1$ and $m_2$ at positions $x_1$ and $x_2$ is defined by the formula [Per the definition of Center of Mass for a system of particles]:

$X_{CM} = \frac{m_H x_H + m_{Cl} x_{Cl}}{m_H + m_{Cl}}$

Step 3: Algebraic Substitution and Calculation

Substituting the given variables into the equation:

$X_{CM} = \frac{m(0) + (35.5m)(1.27 \times 10^{-10} \, \text{m})}{m + 35.5m}$

Factor out and cancel the mass variable $m$ from the numerator and denominator [By Algebraic Simplification]:

$X_{CM} = \frac{35.5 \times 1.27 \times 10^{-10} \, \text{m}}{36.5}$ $X_{CM} = \frac{45.085}{36.5} \times 10^{-10} \, \text{m}$ $X_{CM} \approx 1.235 \times 10^{-10} \, \text{m}$

Step 4: Geometric Representation

H (x=0) Cl (x=1.27 Ã…) CM

Analytical Interpretation

The calculation reveals that the center of mass is significantly closer to the Chlorine nucleus. This is consistent with the physical principle that the CM of a two-body system always lies closer to the more massive body [Per the properties of Center of Mass].

Final Solution: The center of mass of the HCl molecule is located at approximately $1.235 \times 10^{-10} \, \text{m}$ (or $1.235 \, \text{Ã…}$) from the Hydrogen nucleus along the line joining the two nuclei.


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