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Q6.9:
A car weighs 1800 kg. The distance between its front and back axles is 1.8 m. Its centre of gravity is 1.05 m behind the front axle. Determine the force exerted by the level ground on each front wheel and each back wheel.

Solution :

Step 1: Given Variables & System Setup

We are given a car with mass $M = 1800 \text{ kg}$. The total distance between the front axle (at point $A$) and the back axle (at point $B$) is $L = 1.8 \text{ m}$. The centre of gravity ($G$) is located at a distance $d_1 = 1.05 \text{ m}$ from the front axle. Consequently, the distance from the back axle is $d_2 = L - d_1 = 1.8 - 1.05 = 0.75 \text{ m}$.

The total weight $W$ of the car acting downwards at the centre of gravity is:

$W = M \times g = 1800 \text{ kg} \times 9.8 \text{ m/s}^2 = 17640 \text{ N}$ [Per Newton's Second Law of Motion]

Step 2: Equilibrium Equations

Let $F_f$ be the total normal force on the front wheels and $F_b$ be the total normal force on the back wheels. For the car to be in translational and rotational equilibrium:

  • Sum of vertical forces: $F_f + F_b = W = 17640 \text{ N}$ [Per the condition of translational equilibrium: $\sum F_y = 0$]
  • Sum of torques about the front axle ($A$): $W \times d_1 - F_b \times L = 0$ [Per the condition of rotational equilibrium: $\sum \tau_A = 0$]

Step 3: Calculation of Normal Forces

Solving for $F_b$ using the torque equation:

$F_b = \frac{W \times d_1}{L} = \frac{17640 \times 1.05}{1.8}$

$F_b = \frac{18522}{1.8} = 10290 \text{ N}$

Now, substitute $F_b$ into the force balance equation to find $F_f$:

$F_f = 17640 - 10290 = 7350 \text{ N}$

Step 4: Force per Wheel

Since there are two wheels on each axle, the force exerted by the ground on each wheel is half of the total force on that axle:

  • Force per front wheel: $F_{f\_wheel} = \frac{7350}{2} = 3675 \text{ N}$
  • Force per back wheel: $F_{b\_wheel} = \frac{10290}{2} = 5145 \text{ N}$
Front (A) Back (B) W=17640N 1.05m 0.75m

Summary Table

Location Total Force (N) Force per Wheel (N)
Front Axle 7350 3675
Back Axle 10290 5145

Final Solution: The force exerted by the ground on each front wheel is 3675 N, and the force exerted on each back wheel is 5145 N.


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