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Q7.21(a):
A solid cylinder rolls up an inclined plane of angle of inclination $30^\circ$. At the bottom of the inclined plane the centre of mass of the cylinder has a speed of 5 m/s. (a) How far will the cylinder go up the plane?

Solution :

Step 1: Identifying Given Variables & Physical Constants

For a solid cylinder rolling up an inclined plane, we define the following parameters:

  • Initial velocity of center of mass ($v$): $5 \text{ m/s}$
  • Angle of inclination ($\theta$): $30^\circ$
  • Moment of inertia of a solid cylinder about its central axis ($I$): $\frac{1}{2}MR^2$ [Per the definition of the moment of inertia for a solid disk/cylinder]
  • Acceleration due to gravity ($g$): $9.8 \text{ m/s}^2$

Step 2: Theoretical Foundation: Conservation of Energy

As the cylinder rolls up the plane, its initial kinetic energy (translational + rotational) is converted into gravitational potential energy at the maximum height ($h$).

Total Initial Kinetic Energy ($K_i$):

$$K_i = K_{\text{trans}} + K_{\text{rot}} = \frac{1}{2}Mv^2 + \frac{1}{2}I\omega^2$$

Since the cylinder rolls without slipping, the angular velocity $\omega$ is related to $v$ by $\omega = \frac{v}{R}$ [Constraint of pure rolling].

$$K_i = \frac{1}{2}Mv^2 + \frac{1}{2}\left(\frac{1}{2}MR^2\right)\left(\frac{v}{R}\right)^2$$ $$K_i = \frac{1}{2}Mv^2 + \frac{1}{4}Mv^2 = \frac{3}{4}Mv^2$$

Step 3: Calculating Distance Along the Incline

At the maximum height $h$, all kinetic energy is converted to potential energy ($U = Mgh$).

$$\frac{3}{4}Mv^2 = Mgh$$ $$h = \frac{3v^2}{4g}$$

Using the geometric relationship between height ($h$) and distance ($d$) along the incline, $h = d \sin \theta$:

$$d = \frac{h}{\sin \theta} = \frac{3v^2}{4g \sin \theta}$$

Step 4: Algebraic Substitution and Numerical Computation

Substitute the known values into the derived equation:

$$d = \frac{3 \times (5)^2}{4 \times 9.8 \times \sin(30^\circ)}$$ $$d = \frac{3 \times 25}{4 \times 9.8 \times 0.5}$$ $$d = \frac{75}{19.6} \approx 3.8265 \text{ m}$$

Step 5: Visual Representation of the System

30° d (distance) h

Final Solution: The cylinder will go up the plane to a distance of approximately $3.83 \text{ meters}$.


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