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Q13.12 (b):
Plot the corresponding reference circle for each of the following simple harmonic motions. Indicate the initial ((t =0)) position of the particle, the radius of the circle, and the angular speed of the rotating particle. For simplicity, the sense of rotation may be fixed to be anticlockwise in every case: ((x) is in cm and (t) is in s). (x = \cos (\pi/6 - t))

Solution :

Step 1: Identifying Standard Parameters

The given Simple Harmonic Motion (SHM) equation is:

$x(t) = \cos\left(\frac{\pi}{6} - t\right)$

The standard equation for SHM in terms of circular motion is represented as:

$x(t) = A \cos(\omega t + \phi)$

Comparing the two equations:

  • Amplitude ($A$): $1 \text{ cm}$
  • Angular speed ($\omega$): $1 \text{ rad/s}$ [Per the coefficient of $t$ in the argument]
  • Phase constant ($\phi$): $\frac{\pi}{6} \text{ rad}$

Step 2: Determining Initial Position ($t=0$)

To find the position of the reference particle at $t=0$ in the circle, we calculate the angle $\theta$ relative to the positive x-axis:

$\theta = \omega t + \phi = (1)(0) + \frac{\pi}{6} = \frac{\pi}{6} \text{ radians}$

Since the rotation is anticlockwise, the particle starts at an angle of $30^\circ$ from the positive x-axis.

Step 3: Geometrical Visualization of the Reference Circle

P (t=0) 30° x y

Step 4: Summary of Motion Characteristics

Parameter Value
Radius ($A$) $1 \text{ cm}$
Angular Speed ($\omega$) $1 \text{ rad/s}$
Initial Angle ($\phi$) $\frac{\pi}{6} \text{ rad (or } 30^\circ\text{)}$
Sense of Rotation Anticlockwise

Final Solution: The reference circle has a radius of $1 \text{ cm}$, the particle rotates at an angular speed of $1 \text{ rad/s}$, and at $t=0$, the particle is positioned at an angle of $\frac{\pi}{6} \text{ rad}$ ($30^\circ$) measured counter-clockwise from the positive x-axis.


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