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Q5.35(b):
A block of mass 15 kg is placed on a long trolley. The coefficient of static friction between the block and the trolley is 0.18. The trolley accelerates from rest with $0.5 m s^{-2}$ for 20 s and then moves with uniform velocity. Discuss the motion of the block as viewed by (b) an observer moving with the trolley.

Solution :

Step 1: Identifying the Physical System and Inertial Frame

In this problem, we analyze the motion of a mass $m = 15 \text{ kg}$ placed on a trolley. We are tasked with describing the motion from the perspective of an observer moving with the trolley. The trolley's acceleration is $a_t = 0.5 \text{ m s}^{-2}$.

The maximum force of static friction available to keep the block stationary relative to the trolley is:

$f_{s,max} = \mu_s N = \mu_s mg$ [By the definition of static friction]

$f_{s,max} = 0.18 \times 15 \text{ kg} \times 9.8 \text{ m s}^{-2} = 26.46 \text{ N}$

Step 2: Analysis of the Pseudo-Force in the Non-Inertial Frame

An observer on the trolley is in a non-inertial frame of reference because the trolley accelerates. To apply Newton’s Laws in this frame, we must introduce a pseudo-force $F_p$ acting on the block in the direction opposite to the trolley's acceleration [Per D'Alembert's Principle].

$F_p = m \times a_t$

$F_p = 15 \text{ kg} \times 0.5 \text{ m s}^{-2} = 7.5 \text{ N}$

Step 3: Evaluating Motion During Acceleration ($0 \le t \le 20 \text{ s}$)

The pseudo-force $F_p = 7.5 \text{ N}$ acts on the block. Since $F_p < f_{s,max}$ ($7.5 \text{ N} < 26.46 \text{ N}$), the force of static friction $f_s$ exactly balances the pseudo-force to keep the block at rest relative to the trolley.

  • Net Force on block (in trolley frame): $\sum F = F_p - f_s = 7.5 \text{ N} - 7.5 \text{ N} = 0$
  • Observation: The block remains stationary on the trolley for the duration of the acceleration phase.

Step 4: Evaluating Motion After Acceleration ($t > 20 \text{ s}$)

At $t = 20 \text{ s}$, the trolley stops accelerating ($a_t = 0$) and moves with a uniform velocity. Consequently, the pseudo-force $F_p$ becomes zero.

  • Net Force on block: $0$
  • Observation: Since no external or pseudo-forces act on the block, it continues to remain at rest relative to the trolley [Per Newton's First Law].
Block (m) Trolley F_p (Pseudo) f_s (Static Friction)

Summary of Observations

Phase Status of Block relative to Trolley Reasoning
$0 \le t \le 20 \text{ s}$ Stationary Static friction ($7.5 \text{ N}$) exceeds pseudo-force ($7.5 \text{ N}$).
$t > 20 \text{ s}$ Stationary Pseudo-force vanishes; no net force acting.

Final Solution: An observer moving with the trolley will perceive the block to be at rest at all times, as the static friction is sufficient to counteract the pseudo-force during acceleration, and no forces act once the trolley moves with uniform velocity.


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