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To construct a triangle

To construct the tangents from point

1) Draw the circle of radius 6cm with center O

2) Draw a radius and extend it outside till P such that OP = 10cm

3) Draw a perpendicular bisector on OP to intersect at M

4) With OM or OP as radius, draw a circle with center M to intersect the previous circle at A and B

5) Join PA and PB

PA and PB are the required tangents.

First draw a line BC=6 cm. 

At point B, using a proctactor measure an angle of 60º and mark a point say P.

Now join B and P and extend the line for a length of more than 5 cm.

with the help of a rounder mark point A on the line BP with a measurement of 5cm.

Now join AC. 

There we have ΔABC.

Now construcy the second triangle whose sides are 3/4 th of the ΔABC.

to do that, draw a line BC which should be 3/4 times of 6cm.

BC=3/4×6 =4.5 cm and also AB=3/4×5=3.75 cm.

Repeat the above steps we used to construct the first triangle taking the new BC and AB values.

1) Draw the circle using the bangle

a) Draw 2 chords inside the circle and then draw their perpendicular bisectors to intersect at O

b) O is the center of the circle

2) Draw a radius and extend it outside till P(from where you want to draw the tangents)

3) Draw a perpendicular bisector on OP to intersect at M

4) With OM or OP as radius, draw a circle with center M to intersect the previous circle at A and B

5) Join PA and PB

PA and PB are the required tangents.

Feel free to reach out for any clarification.