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Q2(i):
Give two different examples of pair of (i) similar figures.

Solution :

Given: The definition of similar figures in geometry, which states that two figures are similar if they have the same shape but not necessarily the same size.

To Find: Two distinct examples of pairs of similar figures.

Theoretical Context: Two polygons are said to be similar if:
1. Their corresponding angles are equal.
2. Their corresponding sides are in the same ratio (proportion).

Visual Representation:

Triangle A Triangle B Circle C Circle D

Step 1: Identifying Example 1 - Equilateral Triangles

Let us consider two equilateral triangles, $\triangle PQR$ and $\triangle ABC$.
In any equilateral triangle, each interior angle is exactly $60^\circ$.
Since all angles in both triangles are $60^\circ$, the condition for equal corresponding angles is satisfied.
Furthermore, the ratio of corresponding sides $\frac{PQ}{AB} = \frac{QR}{BC} = \frac{RP}{CA}$ is constant.
Therefore, any two equilateral triangles are similar figures.

Step 2: Identifying Example 2 - Circles

Let us consider two circles with radii $r_1$ and $r_2$ respectively.
A circle is defined by the set of all points in a plane that are at a fixed distance (radius) from a fixed point (center).
Because all circles have the same round shape and lack corners, they are geometrically similar.
The ratio of their circumferences ($2\pi r_1 : 2\pi r_2$) and the ratio of their diameters ($2r_1 : 2r_2$) both simplify to the ratio of their radii ($r_1 : r_2$).
Therefore, any two circles are similar figures.

Final Answer: Two examples of pairs of similar figures are:
1. Any two equilateral triangles.
2. Any two circles.


More Questions from Class 10 Mathematics Triangles EXERCISE 6.1


CBSE Solutions for Class 10 Mathematics Triangles


Chapters in CBSE - Class 10 Mathematics


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