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Q3:

State whether the following quadrilaterals are similar or not:

Solution :

Given: Two quadrilaterals, $PQRS$ and $ABCD$.

In quadrilateral $PQRS$: $PQ = 1.5\text{ cm}$, $QR = 1.5\text{ cm}$, $RS = 1.5\text{ cm}$, $SP = 1.5\text{ cm}$. All angles are $90^\circ$.

In quadrilateral $ABCD$: $AB = 3\text{ cm}$, $BC = 3\text{ cm}$, $CD = 3\text{ cm}$, $DA = 3\text{ cm}$. All angles are not $90^\circ$ (they are rhombic angles).

To Find: Determine whether the quadrilaterals $PQRS$ and $ABCD$ are similar.

P Q R S 1.5 A B C D 3

Step 1: Define the conditions for similarity of polygons.

Two polygons of the same number of sides are similar if:

(i) Their corresponding angles are equal.

(ii) Their corresponding sides are in the same ratio (proportion).

Step 2: Check the ratio of corresponding sides.

Let us calculate the ratio of the sides of $PQRS$ to $ABCD$:

$\frac{PQ}{AB} = \frac{1.5}{3} = \frac{1}{2}$

$\frac{QR}{BC} = \frac{1.5}{3} = \frac{1}{2}$

$\frac{RS}{CD} = \frac{1.5}{3} = \frac{1}{2}$

$\frac{SP}{DA} = \frac{1.5}{3} = \frac{1}{2}$

[Since all ratios are equal to $\frac{1}{2}$, the sides are in proportion.]

Step 3: Check the corresponding angles.

In quadrilateral $PQRS$, all angles are $90^\circ$ (it is a square).

In quadrilateral $ABCD$, the angles are not $90^\circ$ (it is a rhombus).

Since the corresponding angles are not equal ($\angle P \neq \angle A$, $\angle Q \neq \angle B$, etc.), the condition for similarity is not satisfied.

Step 4: Conclusion.

For two polygons to be similar, both conditions (proportional sides and equal angles) must be satisfied simultaneously. Since the angles of $PQRS$ and $ABCD$ are not equal, the quadrilaterals are not similar.

Final Answer: The quadrilaterals $PQRS$ and $ABCD$ are not similar because, although their corresponding sides are in the same ratio, their corresponding angles are not equal.


More Questions from Class 10 Mathematics Triangles EXERCISE 6.1


CBSE Solutions for Class 10 Mathematics Triangles


Chapters in CBSE - Class 10 Mathematics


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