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Q9:
Find the coordinates of the points which divide the line segment joining A(– 2, 2) and B(2, 8) into four equal parts.

Solution :

Given: The coordinates of the endpoints of the line segment are $A(-2, 2)$ and $B(2, 8)$.

To Find: The coordinates of the three points $P$, $Q$, and $R$ that divide the line segment $AB$ into four equal parts.

A(-2, 2) P Q R B(2, 8)

Theoretical Basis: The Section Formula states that the coordinates of a point $P(x, y)$ dividing the line segment joining $A(x_1, y_1)$ and $B(x_2, y_2)$ in the ratio $m:n$ are given by:

$x = \frac{mx_2 + nx_1}{m+n}$, $y = \frac{my_2 + ny_1}{m+n}$

Step 1: Finding point Q (The Midpoint of AB)

Since $Q$ divides $AB$ into four equal parts, $Q$ is the midpoint of $AB$. The ratio is $1:1$.

$x_Q = \frac{-2 + 2}{2} = \frac{0}{2} = 0$

$y_Q = \frac{2 + 8}{2} = \frac{10}{2} = 5$

Thus, $Q = (0, 5)$.

Step 2: Finding point P (The Midpoint of AQ)

Point $P$ is the midpoint of the segment $AQ$, where $A = (-2, 2)$ and $Q = (0, 5)$.

$x_P = \frac{-2 + 0}{2} = \frac{-2}{2} = -1$

$y_P = \frac{2 + 5}{2} = \frac{7}{2} = 3.5$

Thus, $P = (-1, 3.5)$.

Step 3: Finding point R (The Midpoint of QB)

Point $R$ is the midpoint of the segment $QB$, where $Q = (0, 5)$ and $B = (2, 8)$.

$x_R = \frac{0 + 2}{2} = \frac{2}{2} = 1$

$y_R = \frac{5 + 8}{2} = \frac{13}{2} = 6.5$

Thus, $R = (1, 6.5)$.

Conclusion: The points dividing the line segment $AB$ into four equal parts are $P(-1, 3.5)$, $Q(0, 5)$, and $R(1, 6.5)$.

Final Answer: The coordinates of the points are $(-1, 3.5)$, $(0, 5)$, and $(1, 6.5)$.


More Questions from Class 10 Mathematics Coordinate geometry EXERCISE 7.2


CBSE Solutions for Class 10 Mathematics Coordinate geometry


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