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Q7:
Find the coordinates of a point A, where AB is the diameter of a circle whose centre is (2, – 3) and B is (1, 4).

Solution :

Given:

1. A circle with center $O$ at coordinates $(2, -3)$.

2. $AB$ is the diameter of the circle.

3. The coordinates of point $B$ are $(1, 4)$.

To Find:

The coordinates of point $A$, let us denote them as $(x, y)$.


O(2, -3) A(x, y) B(1, 4)

Step 1: Theoretical Basis

In a circle, the center $O$ is the midpoint of any diameter $AB$. According to the Midpoint Formula, if a line segment has endpoints $(x_1, y_1)$ and $(x_2, y_2)$, the midpoint $(x_m, y_m)$ is given by:

$x_m = \frac{x_1 + x_2}{2}$

$y_m = \frac{y_1 + y_2}{2}$


Step 2: Assigning Variables

Let the coordinates of point $A$ be $(x, y)$.

Let the coordinates of point $B$ be $(x_2, y_2) = (1, 4)$.

Let the coordinates of the center $O$ be $(x_m, y_m) = (2, -3)$.


Step 3: Calculating the x-coordinate of A

Using the midpoint formula for the x-coordinate:

$2 = \frac{x + 1}{2}$

[Multiplying both sides by 2]

$4 = x + 1$

[Subtracting 1 from both sides]

$x = 4 - 1$

$x = 3$


Step 4: Calculating the y-coordinate of A

Using the midpoint formula for the y-coordinate:

$-3 = \frac{y + 4}{2}$

[Multiplying both sides by 2]

$-6 = y + 4$

[Subtracting 4 from both sides]

$y = -6 - 4$

$y = -10$


Final Answer: The coordinates of point A are (3, -10).


More Questions from Class 10 Mathematics Coordinate geometry EXERCISE 7.2


CBSE Solutions for Class 10 Mathematics Coordinate geometry


Chapters in CBSE - Class 10 Mathematics


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