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Q4:
Check whether (5, – 2), (6, 4) and (7, – 2) are the vertices of an isosceles triangle.
Solution :
Given: Three points in a Cartesian plane: $A(5, -2)$, $B(6, 4)$, and $C(7, -2)$.
To Find: Determine whether the triangle formed by these vertices is an isosceles triangle.
Definition: An isosceles triangle is a triangle in which at least two sides are equal in length.
Formula: The distance $d$ between two points $(x_1, y_1)$ and $(x_2, y_2)$ is given by the Distance Formula:
$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$
Step 1: Calculate the length of side $AB$
Let $A = (5, -2)$ and $B = (6, 4)$.
$AB = \sqrt{(6 - 5)^2 + (4 - (-2))^2}$
$AB = \sqrt{(1)^2 + (4 + 2)^2}$
$AB = \sqrt{1^2 + 6^2}$
$AB = \sqrt{1 + 36}$
$AB = \sqrt{37}$ units
Step 2: Calculate the length of side $BC$
Let $B = (6, 4)$ and $C = (7, -2)$.
$BC = \sqrt{(7 - 6)^2 + (-2 - 4)^2}$
$BC = \sqrt{(1)^2 + (-6)^2}$
$BC = \sqrt{1 + 36}$
$BC = \sqrt{37}$ units
Step 3: Calculate the length of side $AC$
Let $A = (5, -2)$ and $C = (7, -2)$.
$AC = \sqrt{(7 - 5)^2 + (-2 - (-2))^2}$
$AC = \sqrt{(2)^2 + (-2 + 2)^2}$
$AC = \sqrt{2^2 + 0^2}$
$AC = \sqrt{4}$
$AC = 2$ units
Step 4: Comparison and Conclusion
We have found the lengths of the sides to be:
$AB = \sqrt{37}$
$BC = \sqrt{37}$
$AC = 2$
[Since $AB = BC = \sqrt{37}$, two sides of the triangle are equal in length.]
Final Answer: Yes, the points (5, – 2), (6, 4) and (7, – 2) are the vertices of an isosceles triangle because two of its sides are equal in length.
More Questions from Class 10 Mathematics Coordinate geometry EXERCISE 7.1
- Q1(i): Find the distance between the following pairs of points : (i) (2, 3), (4, 1)
- Q1(ii): Find the distance between the following pairs of points : (ii) (– 5, 7), (– 1, 3)
- Q1(iii): Find the distance between the following pairs of points : (iii) ($a$, $b$), (– $a$, – $b$)
- Q10: Find a relation between $x$ and $y$ such that the point ($x$, $y$) is equidistant from the point (3, 6) and (– 3, 4).
- Q2: Find the distance between the points (0, 0) and (36, 15). Can you now find the distance between the two towns A and B.
- Q3: Determine if the points (1, 5), (2, 3) and (– 2, – 11) are collinear.
- Q5: In a classroom, 4 friends are seated at the points A, B, C and D as shown in Fig. 7.8. Champa and Chameli walk into the class and after observing for a few minutes Champa asks Chameli, “Don’t you think ABCD is a square?” Chameli disagrees. Using distance formula, find which of them is correct.
- Q6(i): Name the type of quadrilateral formed, if any, by the following points, and give reasons for your answer: (i) (– 1, – 2), (1, 0), (– 1, 2), (– 3, 0)
- Q6(ii): Name the type of quadrilateral formed, if any, by the following points, and give reasons for your answer: (ii) (–3, 5), (3, 1), (0, 3), (–1, – 4)
- Q6(iii): Name the type of quadrilateral formed, if any, by the following points, and give reasons for your answer: (iii) (4, 5), (7, 6), (4, 3), (1, 2)
- Q7: Find the point on the x-axis which is equidistant from (2, –5) and (–2, 9).
- Q8: Find the values of $y$ for which the distance between the points P(2, – 3) and Q(10, $y$) is 10 units.
- Q9: If Q(0, 1) is equidistant from P(5, –3) and R($x$, 6), find the values of $x$. Also find the distances QR and PR.
CBSE Solutions for Class 10 Mathematics Coordinate geometry
Chapters in CBSE - Class 10 Mathematics
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