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Somesh Shinde Class I-V Tuition trainer in Pune

Somesh Shinde

locationImg Sadashiv Peth, Pune
students 1 student
rsIcon 225 per hour
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Education

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Teaching is more than just a hobby to me. I always think that it can be done in different way. I am a student all my life and i have learn that teacher can the the way in which student think. World can be a better place with a good teacher.

Languages Spoken

Marathi Mother Tongue (Native)

Hindi Proficient

English Basic

Education

INDIAN MARITIME UNIVERSITY Pursuing

Bachelor of Technology (B.Tech.)

INDIAN MARITIME UNIVERSITY KOLKATA CAMPUS Pursuing

2nd semester

INDIAN MARITIME UNIVERSITY KOLKATA CAMPUS Pursuing

Statement of marks

Address

Sadashiv Peth, Pune, India - 411030

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Teaches

Class I-V Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Fees

₹ 225.0 per hour

Board

CBSE, State

Subjects taught

Marathi, Mathematics, Science

Taught in School or College

No

Class 12 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Board

ISC/ICSE, State, CBSE

Subjects taught

English, Chemistry, Mathematics, Hindi, Physics, Logic, Philosophy, Psychology

Taught in School or College

No

Class 11 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Board

State, CBSE

Subjects taught

Mathematics, Chemistry, Physics, Logic, Marathi

Taught in School or College

No

Class 10 Tuition
1 Student

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Board

CBSE, State, ICSE

Subjects taught

Hindi, Science, Mathematics, Marathi, Physics, Chemistry

Taught in School or College

No

Class 9 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Board

CBSE, State, ICSE

Subjects taught

Mathematics, Marathi, Physics, Hindi, Science

Taught in School or College

No

Class 8 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Board

CBSE, ICSE, State

Subjects taught

Marathi, Hindi, Mathematics, Science, Physics, Chemistry

Taught in School or College

No

BCom Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

BCom Subject

Business Mathematics and Statistics

Class strength catered to

One on one/ Private Tutions

Taught in School or College

No

BTech Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

BTech Mechanical subjects

Elasticity & Plasticity, Fluid Mechanics, Strength of Materials, Heat & Mass Transfer

BTech Branch

BTech Mechanical Engineering

Type of class

Regular Classes

Class strength catered to

One on one/ Private Tutions

Taught in School or College

No

Class 6 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Board

CBSE, ICSE, State

Subjects taught

Social science, Science, Hindi, Physics, Mathematics, Marathi

Taught in School or College

No

Class 7 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Board

CBSE, ICSE, State

Subjects taught

Marathi, Chemistry, Hindi, Physics, Science, Mathematics

Taught in School or College

No

Reviews

No Reviews yet!

Answers by Somesh Shinde (3)

Answered on 09/09/2019 Learn CBSE - Class 12/Mathematics/Integrals/NCERT Solutions/Exercise 7.4

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Post a Lesson

Step 1: Take 9 common from the denominator Step 2: Now make the denominater a perfect square in term of x Step 3: Now denominater may look like x^2+a^2 Step 4: now solve it
Answers 3 Comments
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Answered on 09/09/2019 Learn CBSE - Class 12/Mathematics/Differential Equations/NCERT Solutions/Exercise 9.5

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Post a Lesson

(x-y)dy=(x+y) dx dy/dx=(x+y) /(x-y) Put y/x =t That gives dy/dx=x(dt/dx) +t Put these two values in above equation The equation become X(dt/dx) +t=(1+t) /(1-t) Solve this or I can help you further
Answers 3 Comments
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Answered on 04/09/2019 Learn CBSE - Class 12/Mathematics/Continuity and Differentiability/NCERT Solutions/Exercise 5.3

Ask a Question

Post a Lesson

Steps to follow : 1st step put x= Then the denominator of bracket become the formula for cos2( ) Step 2 :invese of cos2( ) becomes sec2( ) Step 3:y=2( ) Step4 :put the value of in term of x Step 5:now you must get something like y=2cos`(x) Step 6: Differentiating this relationship with respect to... ...more

 

Steps to follow :

1st step put x= 

Then the denominator of bracket become the formula for cos2( )

Step 2 :invese of cos2( ) becomes sec2( )

Step 3:y=2( )

Step4 :put the value of  in term of x

Step 5:now you must get something like y=2cos`(x)

Step 6: Differentiating this relationship with respect to x, we obtain

 

 

Answers 2 Comments
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Please select a Tag

Teaches

Class I-V Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Fees

₹ 225.0 per hour

Board

CBSE, State

Subjects taught

Marathi, Mathematics, Science

Taught in School or College

No

Class 12 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Board

ISC/ICSE, State, CBSE

Subjects taught

English, Chemistry, Mathematics, Hindi, Physics, Logic, Philosophy, Psychology

Taught in School or College

No

Class 11 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Board

State, CBSE

Subjects taught

Mathematics, Chemistry, Physics, Logic, Marathi

Taught in School or College

No

Class 10 Tuition
1 Student

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Board

CBSE, State, ICSE

Subjects taught

Hindi, Science, Mathematics, Marathi, Physics, Chemistry

Taught in School or College

No

Class 9 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Board

CBSE, State, ICSE

Subjects taught

Mathematics, Marathi, Physics, Hindi, Science

Taught in School or College

No

Class 8 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Board

CBSE, ICSE, State

Subjects taught

Marathi, Hindi, Mathematics, Science, Physics, Chemistry

Taught in School or College

No

BCom Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

BCom Subject

Business Mathematics and Statistics

Class strength catered to

One on one/ Private Tutions

Taught in School or College

No

BTech Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

BTech Mechanical subjects

Elasticity & Plasticity, Fluid Mechanics, Strength of Materials, Heat & Mass Transfer

BTech Branch

BTech Mechanical Engineering

Type of class

Regular Classes

Class strength catered to

One on one/ Private Tutions

Taught in School or College

No

Class 6 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Board

CBSE, ICSE, State

Subjects taught

Social science, Science, Hindi, Physics, Mathematics, Marathi

Taught in School or College

No

Class 7 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Board

CBSE, ICSE, State

Subjects taught

Marathi, Chemistry, Hindi, Physics, Science, Mathematics

Taught in School or College

No

No Reviews yet!

Answers by Somesh Shinde

Answered on 09/09/2019 Learn CBSE - Class 12/Mathematics/Integrals/NCERT Solutions/Exercise 7.4

Ask a Question

Post a Lesson

Step 1: Take 9 common from the denominator Step 2: Now make the denominater a perfect square in term of x Step 3: Now denominater may look like x^2+a^2 Step 4: now solve it
Answers 3 Comments
Dislike Bookmark

Answered on 09/09/2019 Learn CBSE - Class 12/Mathematics/Differential Equations/NCERT Solutions/Exercise 9.5

Ask a Question

Post a Lesson

(x-y)dy=(x+y) dx dy/dx=(x+y) /(x-y) Put y/x =t That gives dy/dx=x(dt/dx) +t Put these two values in above equation The equation become X(dt/dx) +t=(1+t) /(1-t) Solve this or I can help you further
Answers 3 Comments
Dislike Bookmark

Answered on 04/09/2019 Learn CBSE - Class 12/Mathematics/Continuity and Differentiability/NCERT Solutions/Exercise 5.3

Ask a Question

Post a Lesson

Steps to follow : 1st step put x= Then the denominator of bracket become the formula for cos2( ) Step 2 :invese of cos2( ) becomes sec2( ) Step 3:y=2( ) Step4 :put the value of in term of x Step 5:now you must get something like y=2cos`(x) Step 6: Differentiating this relationship with respect to... ...more

 

Steps to follow :

1st step put x= 

Then the denominator of bracket become the formula for cos2( )

Step 2 :invese of cos2( ) becomes sec2( )

Step 3:y=2( )

Step4 :put the value of  in term of x

Step 5:now you must get something like y=2cos`(x)

Step 6: Differentiating this relationship with respect to x, we obtain

 

 

Answers 2 Comments
Dislike Bookmark
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