4 yrs of Exp 
4 students 
Bhatrapally, Kolkata Details verified of Mandira R.✕
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Share this profile Bengali Mother Tongue (Native)
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BP Poddar Pursuing
Bachelor of Technology (B.Tech.)
Bhatrapally, Kolkata, India - 700126
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Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 11 Tuition
4
Board
State
Subjects taught
Physics, Computer Science, Mathematics, Biology
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
2
Board
ICSE, CBSE, State
Subjects taught
Chemistry, Mathematics, Physics, Science
Taught in School or College
No
1 Student Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 9 Tuition
2
Board
ICSE, CBSE, State
Subjects taught
Mathematics, Physics, Chemistry, Social Science
Taught in School or College
No
1 Student Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
2
Board
CBSE, ISC/ICSE, State
Subjects taught
Biotechnology, Computer Science, Mathematics
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Engineering Entrance Coaching classes
2
Engineering Entrance Exams
IIT JEE Coaching Classes, EAMCET, Delhi CEE Coaching Classes
IITJEE Coaching
IIT JEE Crash Course, IIT JEE Foundation Course, IIT JEE Mains Coaching
Type of class
Crash Course, Regular Classes
IIT-JEE Subjects
Maths
1 Student Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 7 Tuition
4
Board
CBSE, ICSE, State
Subjects taught
Science, Computer Science, Chemistry, Physics, Computers, Mathematics
Taught in School or College
No
1 Student Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 8 Tuition
4
Board
CBSE, ICSE, State
Subjects taught
Mathematics, Physics, Computer Science, Chemistry, Science
Taught in School or College
No
Answered on 13/08/2020 Learn CBSE - Class 11
Ask a Question
Post a Lesson
logx dx = ∫ logx.1 dx f(x) = logx , g(x) = 1 [∫ f(x) g(x) dx = f(x) ∫ g(x) dx - ∫f'(x) (∫ g(x) dx) dx ], ∫ logx.1 dx = logx .x - ∫ 1/x ( x ) dx = x logx -x + c
Like 0 
Answers 218 
Comments Ask a Question
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Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 11 Tuition
4
Board
State
Subjects taught
Physics, Computer Science, Mathematics, Biology
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
2
Board
ICSE, CBSE, State
Subjects taught
Chemistry, Mathematics, Physics, Science
Taught in School or College
No
1 Student Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 9 Tuition
2
Board
ICSE, CBSE, State
Subjects taught
Mathematics, Physics, Chemistry, Social Science
Taught in School or College
No
1 Student Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
2
Board
CBSE, ISC/ICSE, State
Subjects taught
Biotechnology, Computer Science, Mathematics
Taught in School or College
No
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Engineering Entrance Coaching classes
2
Engineering Entrance Exams
IIT JEE Coaching Classes, EAMCET, Delhi CEE Coaching Classes
IITJEE Coaching
IIT JEE Crash Course, IIT JEE Foundation Course, IIT JEE Mains Coaching
Type of class
Crash Course, Regular Classes
IIT-JEE Subjects
Maths
1 Student Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 7 Tuition
4
Board
CBSE, ICSE, State
Subjects taught
Science, Computer Science, Chemistry, Physics, Computers, Mathematics
Taught in School or College
No
1 Student Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 8 Tuition
4
Board
CBSE, ICSE, State
Subjects taught
Mathematics, Physics, Computer Science, Chemistry, Science
Taught in School or College
No
Answered on 13/08/2020 Learn CBSE - Class 11
Ask a Question
Post a Lesson
logx dx = ∫ logx.1 dx f(x) = logx , g(x) = 1 [∫ f(x) g(x) dx = f(x) ∫ g(x) dx - ∫f'(x) (∫ g(x) dx) dx ], ∫ logx.1 dx = logx .x - ∫ 1/x ( x ) dx = x logx -x + c
Like 0 Answers 218 Comments Ask a Question
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