Ballygunge Park Circus, Kolkata 
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Share this profile English Proficient
Bengali Proficient
Hindi Basic
calcutta university 2016
Bachelor of Education (B.Ed.)
Calcutta agency 2015
Graduate
Ballygunge Park Circus, Kolkata, India - 700017
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8 Students Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
7
Board
ICSE, State, CBSE
Preferred class strength
Group Classes, One on one/ Private Tutions
Subjects taught
English, Mathematics, Physics, EVS, English Literature, Biology, Social Science, Bengali, Chemistry, Science
Taught in School or College
Yes
Teaching Experience in detail in Class 10 Tuition
I teach science maths and eng
4 Students Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 9 Tuition
7
Board
ICSE, State, CBSE
Preferred class strength
Group Classes, One on one/ Private Tutions
Experience in School or College
I have taught in a private school earlier. Jibreel internation school.
Subjects taught
Social Science, English Literature, Biology, English, Chemistry, Science, Physics, Mathematics
Taught in School or College
Yes
Teaching Experience in detail in Class 9 Tuition
I have been teaching since 5 years. I teach all subject v-x and english maths xi xii.
2 Students Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 11 Tuition
7
Board
CBSE, State, ISC/ICSE
Preferred class strength
Group Classes, One on one/ Private Tutions
Experience in School or College
It was a good experience
Subjects taught
Mathematics, Chemistry, Physics, English Literature, English
Taught in School or College
Yes
1 Student Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 8 Tuition
7
Board
State, CBSE, ICSE
Preferred class strength
Group Classes, One on one/ Private Tutions
Experience in School or College
It was great
Subjects taught
Social science, Physics, English, Science, Biology, Chemistry, EVS, Geography, Mathematics, Bengali, History
Taught in School or College
Yes
2 Students Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 7 Tuition
7
Board
State, CBSE, ICSE
Experience in School or College
It was nice.
Subjects taught
Geography, English, History, EVS, Mathematics, Social science, Physics, Science, Chemistry, Biology
Taught in School or College
Yes
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 6 Tuition
7
Board
State, CBSE, ICSE, International Baccalaureate
Experience in School or College
Veey nice
Subjects taught
Mathematics, Science, History, Physical Education, Biology, English, Chemistry, Physics, Social science, EVS
Taught in School or College
Yes
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
7
Board
IGCSE, CBSE, State, ISC/ICSE, NIOS, International Baccalaureate
Preferred class strength
Group Classes, One on one/ Private Tutions
Experience in School or College
I have taught for 6 months in jibreel school for experience
Subjects taught
Mathematics, Chemistry, English, Physics, English Literature
Taught in School or College
Yes
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Answered on 22/07/2020 Learn CBSE - Class 11/Physics
Ask a Question
Post a Lesson
Like 0 
Answers 111 
Comments Answered on 16/09/2019 Learn CBSE - Class 8/Maths/Rational Number/NCERT Solutions/Exercise 1.1
Ask a Question
Post a Lesson
Like 0 Answers 9 Comments Answered on 12/09/2019 Learn CBSE - Class 9/Mathematics/Mensuration/Heron's formula/NCERT Solutions/Exercise 12.1
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Post a Lesson
The third side of the triangle will be 30-(12+12)cm
= 30-24 = 6cm.
Therefore the area of the triangle
= √S(s-a)(s-b)(s-c)
√15(15-12)(15-12)(15-6)
√15×3×3×9
9√15cm²
Answer : Area of the triangle is 9√15cm²
Like 0 Answers 10 Comments Answered on 12/09/2019 Learn CBSE - Class 9/Mathematics/Mensuration/Heron's formula/NCERT Solutions/Exercise 12.1
Ask a Question
Post a Lesson
Lets the sides be 12x ,17x and 25x respectively.
Its perimeter = 12x + 17x + 25x which is 540cm
Therefore , according to the question
12x +17x+25x = 540
29x +25x = 540
54x = 540
X = 540/54
X = 10.
Therefore the sides are 12×10 =120
17×10= 170
25×10 = 250
Therefore area of the triangle = √S(s-a)(s-b)(s-c)
=√270(270-120)(270-170)(270-250)
=√270×150×100×20
=√3×3×3×2×5×3×5×2×5×2×2×5×5×2×2×5
=9000cm²
Area of the triangle is 9000cm²
Like 0 Answers 11 Comments Answered on 12/09/2019 Learn CBSE - Class 9/Mathematics/Mensuration/Heron's formula/NCERT Solutions/Exercise 12.1
Ask a Question
Post a Lesson
Lets the sides be 12x ,17x and 25x respectively.
Its perimeter = 12x + 17x + 25x which is 540cm
Therefore , according to the question
12x +17x+25x = 540
29x +25x = 540
54x = 540
X = 540/54
X = 10.
Therefore the sides are 12×10 =120
17×10= 170
25×10 = 250
Therefore area of the triangle = √S(s-a)(s-b)(s-c)
=√270(270-120)(270-170)(270-250)
=√270×150×100×20
=√3×3×3×10×3×5×10×2×2×5×5×2×10
=9000cm²
Area of the triangle is 9000cm²
Like 0 Answers 11 Comments Ask a Question
Also have a look at
8 Students Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
7
Board
ICSE, State, CBSE
Preferred class strength
Group Classes, One on one/ Private Tutions
Subjects taught
English, Mathematics, Physics, EVS, English Literature, Biology, Social Science, Bengali, Chemistry, Science
Taught in School or College
Yes
Teaching Experience in detail in Class 10 Tuition
I teach science maths and eng
4 Students Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 9 Tuition
7
Board
ICSE, State, CBSE
Preferred class strength
Group Classes, One on one/ Private Tutions
Experience in School or College
I have taught in a private school earlier. Jibreel internation school.
Subjects taught
Social Science, English Literature, Biology, English, Chemistry, Science, Physics, Mathematics
Taught in School or College
Yes
Teaching Experience in detail in Class 9 Tuition
I have been teaching since 5 years. I teach all subject v-x and english maths xi xii.
2 Students Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 11 Tuition
7
Board
CBSE, State, ISC/ICSE
Preferred class strength
Group Classes, One on one/ Private Tutions
Experience in School or College
It was a good experience
Subjects taught
Mathematics, Chemistry, Physics, English Literature, English
Taught in School or College
Yes
1 Student Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 8 Tuition
7
Board
State, CBSE, ICSE
Preferred class strength
Group Classes, One on one/ Private Tutions
Experience in School or College
It was great
Subjects taught
Social science, Physics, English, Science, Biology, Chemistry, EVS, Geography, Mathematics, Bengali, History
Taught in School or College
Yes
2 Students Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 7 Tuition
7
Board
State, CBSE, ICSE
Experience in School or College
It was nice.
Subjects taught
Geography, English, History, EVS, Mathematics, Social science, Physics, Science, Chemistry, Biology
Taught in School or College
Yes
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 6 Tuition
7
Board
State, CBSE, ICSE, International Baccalaureate
Experience in School or College
Veey nice
Subjects taught
Mathematics, Science, History, Physical Education, Biology, English, Chemistry, Physics, Social science, EVS
Taught in School or College
Yes
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
7
Board
IGCSE, CBSE, State, ISC/ICSE, NIOS, International Baccalaureate
Preferred class strength
Group Classes, One on one/ Private Tutions
Experience in School or College
I have taught for 6 months in jibreel school for experience
Subjects taught
Mathematics, Chemistry, English, Physics, English Literature
Taught in School or College
Yes
Class Location
Online class via Zoom
Student's Home
Tutor's Home
Answered on 22/07/2020 Learn CBSE - Class 11/Physics
Ask a Question
Post a Lesson
Like 0 Answers 111 Comments Answered on 16/09/2019 Learn CBSE - Class 8/Maths/Rational Number/NCERT Solutions/Exercise 1.1
Ask a Question
Post a Lesson
Like 0 Answers 9 Comments Answered on 12/09/2019 Learn CBSE - Class 9/Mathematics/Mensuration/Heron's formula/NCERT Solutions/Exercise 12.1
Ask a Question
Post a Lesson
The third side of the triangle will be 30-(12+12)cm
= 30-24 = 6cm.
Therefore the area of the triangle
= √S(s-a)(s-b)(s-c)
√15(15-12)(15-12)(15-6)
√15×3×3×9
9√15cm²
Answer : Area of the triangle is 9√15cm²
Like 0 Answers 10 Comments Answered on 12/09/2019 Learn CBSE - Class 9/Mathematics/Mensuration/Heron's formula/NCERT Solutions/Exercise 12.1
Ask a Question
Post a Lesson
Lets the sides be 12x ,17x and 25x respectively.
Its perimeter = 12x + 17x + 25x which is 540cm
Therefore , according to the question
12x +17x+25x = 540
29x +25x = 540
54x = 540
X = 540/54
X = 10.
Therefore the sides are 12×10 =120
17×10= 170
25×10 = 250
Therefore area of the triangle = √S(s-a)(s-b)(s-c)
=√270(270-120)(270-170)(270-250)
=√270×150×100×20
=√3×3×3×2×5×3×5×2×5×2×2×5×5×2×2×5
=9000cm²
Area of the triangle is 9000cm²
Like 0 Answers 11 Comments Answered on 12/09/2019 Learn CBSE - Class 9/Mathematics/Mensuration/Heron's formula/NCERT Solutions/Exercise 12.1
Ask a Question
Post a Lesson
Lets the sides be 12x ,17x and 25x respectively.
Its perimeter = 12x + 17x + 25x which is 540cm
Therefore , according to the question
12x +17x+25x = 540
29x +25x = 540
54x = 540
X = 540/54
X = 10.
Therefore the sides are 12×10 =120
17×10= 170
25×10 = 250
Therefore area of the triangle = √S(s-a)(s-b)(s-c)
=√270(270-120)(270-170)(270-250)
=√270×150×100×20
=√3×3×3×10×3×5×10×2×2×5×5×2×10
=9000cm²
Area of the triangle is 9000cm²
Like 0 Answers 11 Comments Ask a Question
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