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BSc Tuition > BSc Tuition in Kanpur > Aravind Banerjee

Aravind Banerjee BSc Tuition trainer in Kanpur loading="eager" fetchpriority="high" decoding="sync" />

Aravind Banerjee

M.Sc.

Kanpur, Kanpur, India - 208001.

20 yrs of Exp 1 Student

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Overview

Research in Physics at Delhi University 1970 -75
Research in Mathematics at TIFR Mumbai 1976 -87
Taught M.Sc. Mathematics at Mumbai University 1986 -87
Taught M.Sc. Mathematics at Goa University 1988-95
Presently retired. Available only at my home in Kanpur .

Languages Spoken

Hindi

English

Bengali

Education

IIT Kanpur 1970

Master of Science (M.Sc.)

Address

Kanpur, Kanpur, India - 208001

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Teaches

BSc Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Years of Experience in BSc Tuition

20

Type of class

Regular Classes

Class strength catered to

One on one/ Private Tutions

Taught in School or College

No

BSc Branch

BSc Mathematics

BSc Mathematics Subjects

Discrete Mathematics, Analysis, Calculus, Number Theory, Algebra

Teaching Experience in detail in BSc Tuition

Taught a few students at my home.

Class 11 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

20

Board

State, CBSE, International Baccalaureate, ISC/ICSE

Subjects taught

Mathematics

Taught in School or College

No

Teaching Experience in detail in Class 11 Tuition

Taught mathematics to a few students at my home.

Class 12 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

20

Board

State, CBSE, International Baccalaureate, ISC/ICSE

Subjects taught

Mathematics

Taught in School or College

No

Teaching Experience in detail in Class 12 Tuition

Taught mathematics to a few students at my home.

Engineering Entrance Coaching classes

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Years of Experience in Engineering Entrance Coaching classes

20

Engineering Entrance Exams

IIT JEE Coaching Classes

Type of class

Regular Classes

Teaching Experience in detail in Engineering Entrance Coaching classes

Taught a few students at my home.

MSc Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Years of Experience in MSc Tuition

20

Subject

Mathematics

Taught in School or College

Yes

Teaching Experience in detail in MSc Tuition

Experience : 25 years of Research and Teaching Research in Physics at Delhi University 1970-75 Research in Mathematics at TIFR Mumbai 1976-87 Taught M.Sc. Mathematics at Mumbai University 1986-87 Taught M.Sc. Mathematics at Goa University 1988-95 Presently retired. Available on-line or at home in Kanpur.

Math Olympiad classes

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Years of Experience in Math Olympiad classes

20

Upcoming Live Classes

Reviews

No Reviews yet!

FAQs

1. Do you have any prior teaching experience?

No

2. Which classes do you teach?

I teach BSc Tuition, Class 11 Tuition, Class 12 Tuition, Engineering Entrance Coaching, MSc Tuition and Math Olympiad Classes.

3. Do you provide a demo class?

Yes, I provide a free demo class.

4. How many years of experience do you have?

I have been teaching for 20 years.

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Answers by Aravind Banerjee (3)

Answered on 12/12/2016 Learn Hyperbola +2 Tuition/Class XI-XII Tuition (PUC)

Prove that the midpoints of chords of the hyperbola (square of x)/(square of a)--(square of y)/(square... ...more
Prove that the midpoints of chords of the hyperbola (square of x)/(square of a)--(square of y)/(square...

Let the cord parallel to y=mx be y=mx+c..............(1) Then the points of intersection with the hyperbola are given by:- x^2/a^2 - (mx+c)^2/b^2 = 1 or (1/a^2-m^2/b^2)x^2-2mxc/b^2-c^2/b^2-1=0 .....(2) Let (x1,y1) and (x2,y2) be the end points of the cord. Then x1 and x2 both satisfy... ...more
Let the cord parallel to y=mx be y=mx+c..............(1) Then the points of intersection with the hyperbola are given by:- x^2/a^2 - (mx+c)^2/b^2 = 1 or (1/a^2-m^2/b^2)x^2-2mxc/b^2-c^2/b^2-1=0 .....(2) Let (x1,y1) and (x2,y2) be the end points of the cord. Then x1 and x2 both satisfy Eq.(2) So x1+x2 = [2mc/b^2]/(1/a^2-m^2/b^2) = 2mc/(b^2/a^2-m^2)...............(3) Let (h,k) be the midpoint of the cord. Then h=(x1+x2)/2 = mc/(b^2/a^2-m^2) and k=(y1+y2)/2. Now both (x1,y1) and (x2,y2) satisfy Eq(1) so that k=mh+c. Substituting the value of c from Eq(3) k=mh+(b^2/a^2-m^2)h/m = b^2/(a^2m) Or a^2 mk = b^2h Therefore the locus of the midpoint (h,k) of the cord is a^2 my = b^2x.
Answers 4 Comments
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Answered on 25/07/2015 Learn Tuition/Class XI-XII Tuition (PUC)

Let P be an interior point of an equilateral triangle ABC, such that AP^2 = BP^2 + CP^2, then find the... ...more
Let P be an interior point of an equilateral triangle ABC, such that AP^2 = BP^2 + CP^2, then find the...

Without loss of generality may assume that the sides of the triangle have length 1. May choose the coordinate axes so that A, B and C have coordinates (0,0), (1,0) and ( 1/2,root(3)/2 ). Let (x,y) be the coordinates of the point P. Then x^2+y^2 = (x-1)^2+y^2+(x-1/2)^2+(y-root(3)/2)^2 . i.e. x^2-3x+5/4+(y-root(3)/2)^2... ...more
Without loss of generality may assume that the sides of the triangle have length 1. May choose the coordinate axes so that A, B and C have coordinates (0,0), (1,0) and ( 1/2,root(3)/2 ). Let (x,y) be the coordinates of the point P. Then x^2+y^2 = (x-1)^2+y^2+(x-1/2)^2+(y-root(3)/2)^2 . i.e. x^2-3x+5/4+(y-root(3)/2)^2 = 0. or (x-3/2)^2+(y-root(3)/2)^2 = 1. Thus the locus of the point P is a circle of radious 1 with the centre at the point D with coordinates (3/2,root(3)/2). It passes through B and C. Clearly ABDC is a parallelogram and so the
Answers 9 Comments
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Answered on 21/07/2015 Learn Tuition/Class XI-XII Tuition (PUC)

Let P be an interior point of an equilateral triangle ABC, such that AP^2 = BP^2 + CP^2, then find the... ...more
Let P be an interior point of an equilateral triangle ABC, such that AP^2 = BP^2 + CP^2, then find the...

Without loss of generality may assume that the sides of the triangle have length 1. May choose the coordinate axes so that A, B and C have coordinates (0,0), (1,0) and ( 1/2,root(3)/2 ). Let (x,y) be the coordinates of the point P. Then x^2+y^2 = (x-1)^2+y^2+(x-1/2)^2+(y-root(3)/2)^2 . i.e. x^2-3x+5/4+(y-root(3)/2)^2... ...more
Without loss of generality may assume that the sides of the triangle have length 1. May choose the coordinate axes so that A, B and C have coordinates (0,0), (1,0) and ( 1/2,root(3)/2 ). Let (x,y) be the coordinates of the point P. Then x^2+y^2 = (x-1)^2+y^2+(x-1/2)^2+(y-root(3)/2)^2 . i.e. x^2-3x+5/4+(y-root(3)/2)^2 = 0. or (x-3/2)^2+(y-root(3)/2)^2 = 1. Thus the locus of the point P is a circle of radius 1 with the center at the point D with coordinates (3/2,root(3)/2). Clearly ABDC is a parallelogram and so the
Answers 9 Comments
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Teaches

BSc Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Years of Experience in BSc Tuition

20

Type of class

Regular Classes

Class strength catered to

One on one/ Private Tutions

Taught in School or College

No

BSc Branch

BSc Mathematics

BSc Mathematics Subjects

Discrete Mathematics, Analysis, Calculus, Number Theory, Algebra

Teaching Experience in detail in BSc Tuition

Taught a few students at my home.

Class 11 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Years of Experience in Class 11 Tuition

20

Board

State, CBSE, International Baccalaureate, ISC/ICSE

Subjects taught

Mathematics

Taught in School or College

No

Teaching Experience in detail in Class 11 Tuition

Taught mathematics to a few students at my home.

Class 12 Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Years of Experience in Class 12 Tuition

20

Board

State, CBSE, International Baccalaureate, ISC/ICSE

Subjects taught

Mathematics

Taught in School or College

No

Teaching Experience in detail in Class 12 Tuition

Taught mathematics to a few students at my home.

Engineering Entrance Coaching classes

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Years of Experience in Engineering Entrance Coaching classes

20

Engineering Entrance Exams

IIT JEE Coaching Classes

Type of class

Regular Classes

Teaching Experience in detail in Engineering Entrance Coaching classes

Taught a few students at my home.

MSc Tuition

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Years of Experience in MSc Tuition

20

Subject

Mathematics

Taught in School or College

Yes

Teaching Experience in detail in MSc Tuition

Experience : 25 years of Research and Teaching Research in Physics at Delhi University 1970-75 Research in Mathematics at TIFR Mumbai 1976-87 Taught M.Sc. Mathematics at Mumbai University 1986-87 Taught M.Sc. Mathematics at Goa University 1988-95 Presently retired. Available on-line or at home in Kanpur.

Math Olympiad classes

Class Location

Online Classes (Video Call via UrbanPro LIVE)

Student's Home

Tutor's Home

Years of Experience in Math Olympiad classes

20

Upcoming Live Classes

No Reviews yet!

Answers by Aravind Banerjee (3)

Answered on 12/12/2016 Learn Hyperbola +2 Tuition/Class XI-XII Tuition (PUC)

Prove that the midpoints of chords of the hyperbola (square of x)/(square of a)--(square of y)/(square... ...more
Prove that the midpoints of chords of the hyperbola (square of x)/(square of a)--(square of y)/(square...

Let the cord parallel to y=mx be y=mx+c..............(1) Then the points of intersection with the hyperbola are given by:- x^2/a^2 - (mx+c)^2/b^2 = 1 or (1/a^2-m^2/b^2)x^2-2mxc/b^2-c^2/b^2-1=0 .....(2) Let (x1,y1) and (x2,y2) be the end points of the cord. Then x1 and x2 both satisfy... ...more
Let the cord parallel to y=mx be y=mx+c..............(1) Then the points of intersection with the hyperbola are given by:- x^2/a^2 - (mx+c)^2/b^2 = 1 or (1/a^2-m^2/b^2)x^2-2mxc/b^2-c^2/b^2-1=0 .....(2) Let (x1,y1) and (x2,y2) be the end points of the cord. Then x1 and x2 both satisfy Eq.(2) So x1+x2 = [2mc/b^2]/(1/a^2-m^2/b^2) = 2mc/(b^2/a^2-m^2)...............(3) Let (h,k) be the midpoint of the cord. Then h=(x1+x2)/2 = mc/(b^2/a^2-m^2) and k=(y1+y2)/2. Now both (x1,y1) and (x2,y2) satisfy Eq(1) so that k=mh+c. Substituting the value of c from Eq(3) k=mh+(b^2/a^2-m^2)h/m = b^2/(a^2m) Or a^2 mk = b^2h Therefore the locus of the midpoint (h,k) of the cord is a^2 my = b^2x.
Answers 4 Comments
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Answered on 25/07/2015 Learn Tuition/Class XI-XII Tuition (PUC)

Let P be an interior point of an equilateral triangle ABC, such that AP^2 = BP^2 + CP^2, then find the... ...more
Let P be an interior point of an equilateral triangle ABC, such that AP^2 = BP^2 + CP^2, then find the...

Without loss of generality may assume that the sides of the triangle have length 1. May choose the coordinate axes so that A, B and C have coordinates (0,0), (1,0) and ( 1/2,root(3)/2 ). Let (x,y) be the coordinates of the point P. Then x^2+y^2 = (x-1)^2+y^2+(x-1/2)^2+(y-root(3)/2)^2 . i.e. x^2-3x+5/4+(y-root(3)/2)^2... ...more
Without loss of generality may assume that the sides of the triangle have length 1. May choose the coordinate axes so that A, B and C have coordinates (0,0), (1,0) and ( 1/2,root(3)/2 ). Let (x,y) be the coordinates of the point P. Then x^2+y^2 = (x-1)^2+y^2+(x-1/2)^2+(y-root(3)/2)^2 . i.e. x^2-3x+5/4+(y-root(3)/2)^2 = 0. or (x-3/2)^2+(y-root(3)/2)^2 = 1. Thus the locus of the point P is a circle of radious 1 with the centre at the point D with coordinates (3/2,root(3)/2). It passes through B and C. Clearly ABDC is a parallelogram and so the
Answers 9 Comments
Dislike Bookmark

Answered on 21/07/2015 Learn Tuition/Class XI-XII Tuition (PUC)

Let P be an interior point of an equilateral triangle ABC, such that AP^2 = BP^2 + CP^2, then find the... ...more
Let P be an interior point of an equilateral triangle ABC, such that AP^2 = BP^2 + CP^2, then find the...

Without loss of generality may assume that the sides of the triangle have length 1. May choose the coordinate axes so that A, B and C have coordinates (0,0), (1,0) and ( 1/2,root(3)/2 ). Let (x,y) be the coordinates of the point P. Then x^2+y^2 = (x-1)^2+y^2+(x-1/2)^2+(y-root(3)/2)^2 . i.e. x^2-3x+5/4+(y-root(3)/2)^2... ...more
Without loss of generality may assume that the sides of the triangle have length 1. May choose the coordinate axes so that A, B and C have coordinates (0,0), (1,0) and ( 1/2,root(3)/2 ). Let (x,y) be the coordinates of the point P. Then x^2+y^2 = (x-1)^2+y^2+(x-1/2)^2+(y-root(3)/2)^2 . i.e. x^2-3x+5/4+(y-root(3)/2)^2 = 0. or (x-3/2)^2+(y-root(3)/2)^2 = 1. Thus the locus of the point P is a circle of radius 1 with the center at the point D with coordinates (3/2,root(3)/2). Clearly ABDC is a parallelogram and so the
Answers 9 Comments
Dislike Bookmark

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Aravind Banerjee conducts classes in BSc Tuition, Class 11 Tuition and Class 12 Tuition. Aravind is located in Kanpur, Kanpur. Aravind takes Regular Classes- at his Home and Online Classes- via online medium. He has 20 years of teaching experience . Aravind has completed Master of Science (M.Sc.) from IIT Kanpur in 1970. He is well versed in Hindi, English and Bengali.

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