Given:

• Area of head = 15 cm × 15 cm

• So, $A = 15 × 15 = 225 \text{ cm}^2$A=15×15=225 cm2

Now we need to find the weight of air above this area — that means we must consider air pressure.

Step 1: Standard atmospheric pressure

At sea level,

$$1 \text{ atmosphere} = 1.013 \times 10^5 \text{ N/m}^2$$1 atmosphere=1.013×105 N/m2

Step 2: Convert area from cm² to m²

$$225 \text{ cm}^2 = 225 × 10^{-4} \text{ m}^2 = 0.0225 \text{ m}^2$$225 cm2=225×10−4 m2=0.0225 m2

Step 3: Force on the head due to air pressure

$$\text{Force} = \text{Pressure} × \text{Area}$$Force=Pressure×Area $$F = 1.013 × 10^5 × 0.0225 = 2280 \text{ N (approximately)}$$F=1.013×105×0.0225=2280 N (approximately)

Step 4: Convert force to equivalent weight (mass)

$$\text{Weight} = mg \implies m = \frac{F}{g}$$Weight=mg⟹m=gF

Using $g = 9.8 \text{ m/s}^2$g=9.8 m/s2:

$$m = \frac{2280}{9.8} ≈ 232.65 \text{ kg}$$m=9.82280≈232.65 kg

✅ Final Answer:
You are carrying approximately 230 kilograms of air on your head due to atmospheric pressure!