true

https://www.urbanpro.com/hyderabad/siddardha/14498381 # Siddardha

## Service and Self Reliance, Futuristic

## Overview

## Languages Spoken

## Education

## Address

## Verified Info

## Demo Class

## BTech Tuition Overview

## Reviews (1)

## FAQs

## Answers by Siddardha (2)

## Answers by Siddardha (2)

### Learn More

Siddardha

Gandhi Nagar, Hyderabad, India - 500020

Gandhi Nagar, Hyderabad, India - 500020.

2

5.0

Details verified of Siddardha✕

Identity

Education

Know how UrbanPro verifies Tutor details

Identity is verified based on matching the details uploaded by the Tutor with government databases.

I am an engineer by education, civil servant by aspiration, tutor by profession(part time). I have been preparing for IAS since completion of my graduation, i have cleared different levels of examinations conducted by staff Selection commission. For self respect and self reliance , self satisfaction i am always willing to share (with others)and expand my knowledge. I am successful if my knowledge helps such person who challenges the odds in his career and life.

With this motive i am interested in teaching, there by shaping the future India.

With this motive i am interested in teaching, there by shaping the future India.

Telugu Mother Tongue (Native)

English Proficient

Hindi Basic

jntu kakinada 2014

Bachelor of Technology (B.Tech.)

1, New Bakaram, Usyatam Residency, Gandhi Nagar, Kavadiguda

-meri gold appartment

Gandhi Nagar, Hyderabad, India - 500020

Landmark: -alex fitness centre

ID Verified

Education Verified

Phone Verified

Email Verified

Yes, not charged

Report this Profile

✕

x

Is this listing inaccurate or duplicate? Any other problem?

Please tell us about the problem and we will fix it.

BTech Tuition

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in BTech Tuition

2

BTech Branch

Other Engineering topics, BTech 1st Year Engineering

Experience in School or College

2 years in vignan college

Type of class

Crash Course, Regular Classes

Class strength catered to

One on one/ Private Tutions

Taught in School or College

Yes

BTech 1st Year subjects

Advanced Mathematics (M2), Engineering Mathematics (M1)

Teaching Experience in detail in BTech Tuition

I have a teaching experience of 2 years in vignan engineering college. I have a very good track record in private tutoring in engineering mathematics with 100 percent pass percentage. Parents of the students concerned like srinivas sir, and many others has congratulated me for my efforts on their children who earlier has math phobia now being passed in mathematics that too in graduate level and there after children are confident enough to tackle any kind of mathematics. My teaching style mostly relies on removing the fear of student and allow themfall in love with mathematics. Real time examples of every topics makes them understand the concept and there Building a confidence in the student in such a way that they are going change the shape of India with their knowledge.

this is test message this is test message this is test message this is test message this is test message this is test message this is test message

5.0 out of 5.0 1 review

Siddardha https://s3-ap-southeast-1.amazonaws.com/tv-prod/member/photo/6993866-small.jpg Gandhi Nagar

5.0051 Siddardha

U

23 Oct, 2019

Umar Wahab attended Class 12 Tuition

"Siddardha sir has a lot of experience in teaching. He is a very good tutor with some exceptional teaching skills. "

Have you attended any class with Siddardha? Write a Review

1. Which BTech branches do you tutor for?

Other Engineering topics and BTech 1st Year Engineering

2. Do you have any prior teaching experience?

Yes

3. Which classes do you teach?

I teach BTech Tuition, Class 10 Tuition, Class 11 Tuition and Class 12 Tuition Classes.

4. Do you provide a demo class?

Yes, I provide a free demo class.

5. How many years of experience do you have?

I have been teaching for 2 years.

Answered on 23/10/2019 CBSE/Class 12/Science/Physics/Unit 1-Electrostatics/ELECTROSTATIC POTENTIAL AND CAPACITANCE/NCERT Solutions/Exercise 2

we know that 1/2 CV2 is the energy stored in a capactor with capacitance C when connected across the voltage source V. the property of capacitor is it acquires charge when it is connected to voltage source. after this was this connected it acts as a energy source untill the charge in it is dissipated... ...more

we know that 1/2 CV2 is the energy stored in a capactor with capacitance C when connected across the voltage source V.

the property of capacitor is it acquires charge when it is connected to voltage source.

after this was this connected it acts as a energy source untill the charge in it is dissipated or until an equal energy source is countered to it.

so in case 1: when it is connected to the 200V source

energy acquired by the 600pF capacitor is 1.2 * 10^{-5 }

that means the energy 1.2 *10^{-5 }is shared between two capacitors in equal amount

that means energy lost is half of the intial total energy and that is equal to energy gained by the second capacitor = 0.6 *10^{-5 }joules

Like 0

Answers 7 Comments Answered on 23/10/2019 CBSE/Class 9

you can do it by grouping two digits together form right like in this case 1369. now start divisionstep 1: choose the number such that its square is close to our left end pair (here 13) 3)1369(3 09 04 69 step 2 : Now multiplie the divisor with 2 (3 *2 =6) choose another number (here... ...more

you can do it by grouping two digits together form right like in this case 1369. now start division

step 1: choose the number such that its square is close to our left end pair (here 13)

3)1369(3

09

04 69

step 2 : Now multiplie the divisor with 2 (3 *2 =6)

choose another number (here 7), to place on the right side of the multiplied divisor (here 6) such that both the digits combined and multiplied with the chosen number will give either the exact value (here 496) or close to our required value.

67)496(7

496

0

so our square root of 1369 is our first digit 3 and our second digit 7 =37

or

for quick calculations follow this method

we know the square of 30 =900

and the square of 40 =1600

so the square of some number between 30 to 40 will be 1369

Now check the middle number, i.e. 35

sq of 35 =1225

that means our required number lies between 35 to 40

Now go for unit digit. Our unit digit is 9, which is given by 3 or 7 only when squared.

From 35 to 40 only 37 square will be 9 as a unit digit.

Our answer is 37.

Like 0

Answers 135 Comments BTech Tuition 5.0

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in BTech Tuition

2

BTech Branch

Other Engineering topics, BTech 1st Year Engineering

Experience in School or College

2 years in vignan college

Type of class

Crash Course, Regular Classes

Class strength catered to

One on one/ Private Tutions

Taught in School or College

Yes

BTech 1st Year subjects

Advanced Mathematics (M2), Engineering Mathematics (M1)

Teaching Experience in detail in BTech Tuition

I have a teaching experience of 2 years in vignan engineering college. I have a very good track record in private tutoring in engineering mathematics with 100 percent pass percentage. Parents of the students concerned like srinivas sir, and many others has congratulated me for my efforts on their children who earlier has math phobia now being passed in mathematics that too in graduate level and there after children are confident enough to tackle any kind of mathematics. My teaching style mostly relies on removing the fear of student and allow themfall in love with mathematics. Real time examples of every topics makes them understand the concept and there Building a confidence in the student in such a way that they are going change the shape of India with their knowledge.

Class 12 Tuition 5.0

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 12 Tuition

4

Board

ISC/ICSE, State, CBSE

ISC/ICSE Subjects taught

Mathematics

CBSE Subjects taught

Mathematics

Taught in School or College

Yes

State Syllabus Subjects taught

Mathematics

Class 11 Tuition 5.0

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 11 Tuition

4

Board

ISC/ICSE, State, CBSE

ISC/ICSE Subjects taught

Mathematics

CBSE Subjects taught

Mathematics

Experience in School or College

i have taught for students in vignan college for 2 years.

Taught in School or College

Yes

State Syllabus Subjects taught

Mathematics

Class 10 Tuition 5.0

Class Location

Student's Home

Tutor's Home

Online (video chat via skype, google hangout etc)

Years of Experience in Class 10 Tuition

4

Board

ICSE, CBSE

CBSE Subjects taught

Mathematics, Science

ICSE Subjects taught

Mathematics, Physics

Taught in School or College

Yes

this is test message this is test message this is test message this is test message this is test message this is test message this is test message

5.0 out of 5.0 1 review

Siddardha

U

23 Oct, 2019

Umar Wahab attended Class 12 Tuition

"Siddardha sir has a lot of experience in teaching. He is a very good tutor with some exceptional teaching skills. "

Have you attended any class with Siddardha? Write a Review

Answered on 23/10/2019 CBSE/Class 12/Science/Physics/Unit 1-Electrostatics/ELECTROSTATIC POTENTIAL AND CAPACITANCE/NCERT Solutions/Exercise 2

we know that 1/2 CV2 is the energy stored in a capactor with capacitance C when connected across the voltage source V. the property of capacitor is it acquires charge when it is connected to voltage source. after this was this connected it acts as a energy source untill the charge in it is dissipated... ...more

we know that 1/2 CV2 is the energy stored in a capactor with capacitance C when connected across the voltage source V.

the property of capacitor is it acquires charge when it is connected to voltage source.

after this was this connected it acts as a energy source untill the charge in it is dissipated or until an equal energy source is countered to it.

so in case 1: when it is connected to the 200V source

energy acquired by the 600pF capacitor is 1.2 * 10^{-5 }

that means the energy 1.2 *10^{-5 }is shared between two capacitors in equal amount

that means energy lost is half of the intial total energy and that is equal to energy gained by the second capacitor = 0.6 *10^{-5 }joules

Like 0

Answers 7 Comments Answered on 23/10/2019 CBSE/Class 9

you can do it by grouping two digits together form right like in this case 1369. now start divisionstep 1: choose the number such that its square is close to our left end pair (here 13) 3)1369(3 09 04 69 step 2 : Now multiplie the divisor with 2 (3 *2 =6) choose another number (here... ...more

step 1: choose the number such that its square is close to our left end pair (here 13)

3)1369(3

09

04 69

step 2 : Now multiplie the divisor with 2 (3 *2 =6)

choose another number (here 7), to place on the right side of the multiplied divisor (here 6) such that both the digits combined and multiplied with the chosen number will give either the exact value (here 496) or close to our required value.

67)496(7

496

0

so our square root of 1369 is our first digit 3 and our second digit 7 =37

or

for quick calculations follow this method

we know the square of 30 =900

and the square of 40 =1600

so the square of some number between 30 to 40 will be 1369

Now check the middle number, i.e. 35

sq of 35 =1225

that means our required number lies between 35 to 40

Now go for unit digit. Our unit digit is 9, which is given by 3 or 7 only when squared.

From 35 to 40 only 37 square will be 9 as a unit digit.

Our answer is 37.

Like 0

Answers 135 Comments Share this Profile

X

Post your Learning Need

Let us shortlist and give the best tutors and institutes.

or

Send Enquiry to Siddardha

Let Siddardha know you are interested in their class

Reply to 's review

Enter your reply*

Your reply has been successfully submitted.