Kukatpally, Hyderabad, India - 500085.
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Telugu Mother Tongue (Native)
English Proficient
Jntuh Pursuing
Bachelor of Technology (B.Tech.)
Kukatpally, Hyderabad, India - 500085
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Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Engineering Entrance Coaching classes
2
Engineering Entrance Exams
BITSAT Coaching Classes, EAMCET, IIT JEE Coaching Classes
IITJEE Coaching
IIT JEE Mains Coaching, IIT JEE Crash Course, IIT JEE Foundation Course, IIT JEE Integrated Coaching
Type of class
Regular Classes, Crash Course
IIT-JEE Subjects
Maths, Physics , Chemistry
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
2
Board
CBSE, State
CBSE Subjects taught
Mathematics, Science
Taught in School or College
No
State Syllabus Subjects taught
EVS, Mathematics, Science
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 11 Tuition
2
Board
State, CBSE
CBSE Subjects taught
Chemistry, Physics, Mathematics
Taught in School or College
No
State Syllabus Subjects taught
Mathematics, Chemistry, Physics
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
2
Board
State, CBSE
CBSE Subjects taught
Chemistry, Physics, Mathematics
Taught in School or College
No
State Syllabus Subjects taught
Mathematics, Chemistry, Physics
1. Which classes do you teach?
I teach Class 10 Tuition, Class 11 Tuition, Class 12 Tuition and Engineering Entrance Coaching Classes.
2. Do you provide a demo class?
Yes, I provide a free demo class.
3. How many years of experience do you have?
I have been teaching for 2 years.
Answered on 20/11/2019 Learn CBSE/Class 12/Science/Physics/Unit 1-Electrostatics/ELECTROSTATIC POTENTIAL AND CAPACITANCE/NCERT Solutions/Exercise 2
According to gauss law,
Φ=q/e Φ=E.A( E=electric field and A=area enclosed by the Gaussian surface)
where q is net charge enclosed by the Gaussian surface and e is the permitivity of free space(8.85*10-12)
Now,
a) inside the sphere charge is zero so Φ=0 and E is also zero ( from above
b) apply above formula with area of sphere =4Π(r)2 and find electric field
C) same as b case but here the radius changes to 18cm .Apply gauss law
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Engineering Entrance Coaching classes
2
Engineering Entrance Exams
BITSAT Coaching Classes, EAMCET, IIT JEE Coaching Classes
IITJEE Coaching
IIT JEE Mains Coaching, IIT JEE Crash Course, IIT JEE Foundation Course, IIT JEE Integrated Coaching
Type of class
Regular Classes, Crash Course
IIT-JEE Subjects
Maths, Physics , Chemistry
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 10 Tuition
2
Board
CBSE, State
CBSE Subjects taught
Mathematics, Science
Taught in School or College
No
State Syllabus Subjects taught
EVS, Mathematics, Science
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 11 Tuition
2
Board
State, CBSE
CBSE Subjects taught
Chemistry, Physics, Mathematics
Taught in School or College
No
State Syllabus Subjects taught
Mathematics, Chemistry, Physics
Class Location
Online (video chat via skype, google hangout etc)
Student's Home
Tutor's Home
Years of Experience in Class 12 Tuition
2
Board
State, CBSE
CBSE Subjects taught
Chemistry, Physics, Mathematics
Taught in School or College
No
State Syllabus Subjects taught
Mathematics, Chemistry, Physics
Answered on 20/11/2019 Learn CBSE/Class 12/Science/Physics/Unit 1-Electrostatics/ELECTROSTATIC POTENTIAL AND CAPACITANCE/NCERT Solutions/Exercise 2
According to gauss law,
Φ=q/e Φ=E.A( E=electric field and A=area enclosed by the Gaussian surface)
where q is net charge enclosed by the Gaussian surface and e is the permitivity of free space(8.85*10-12)
Now,
a) inside the sphere charge is zero so Φ=0 and E is also zero ( from above
b) apply above formula with area of sphere =4Π(r)2 and find electric field
C) same as b case but here the radius changes to 18cm .Apply gauss law
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